我有一個像這樣的 xml 檔案，XML1：
<?xml version='1.0' encoding='utf-8'?>
<report>
</report>
另一個是這樣的，XML2：
<?xml version='1.0' encoding='utf-8'?>
<report attrib1="blabla" attrib2="blabla" attrib3="blabla" attrib4="blabla" attrib5="blabla" >
<child1>
<child2>
....
</child2>
</child1>
</report>
我需要替換并放置沒有子元素的 XML2 的根元素，所以 XML1 看起來像這樣：
<?xml version='1.0' encoding='utf-8'?>
<report attrib1="blabla" attrib2="blabla" attrib3="blabla" attrib4="blabla" attrib5="blabla">
</report>
目前我的代碼看起來像這樣，但它不會洗掉孩子，而是將整棵樹放在里面：
source_tree = ET.parse('XML2.xml')
source_root = source_tree.getroot()
report = source_root.findall('report')
for child in list(report):
report.remove(child)
source_tree.write('XML1.xml', encoding='utf-8', xml_declaration=True)
任何人都知道我怎樣才能做到這一點？
謝謝！
uj5u.com熱心網友回復：
嘗試以下（只需復制attrib）
import xml.etree.ElementTree as ET
xml1 = '''<?xml version='1.0' encoding='utf-8'?>
<report>
</report>'''
xml2 = '''<?xml version='1.0' encoding='utf-8'?>
<report attrib1="blabla" attrib2="blabla" attrib3="blabla" attrib4="blabla" attrib5="blabla" >
<child1>
<child2>
</child2>
</child1>
</report>'''
root1 = ET.fromstring(xml1)
root2 = ET.fromstring(xml2)
root1.attrib = root2.attrib
ET.dump(root1)
輸出
<report attrib1="blabla" attrib2="blabla" attrib3="blabla" attrib4="blabla" attrib5="blabla">
</report>
uj5u.com熱心網友回復：
所以這里是作業代碼：
source_tree = ET.parse('XML2.xml')
source_root = source_tree.getroot()
dest_tree = ET.parse('XML1.xml')
dest_root = dest_tree.getroot()
dest_root.attrib = source_root.attrib
dest_tree.write('XML1.xml', encoding='utf-8', xml_declaration=True)
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