嗨,我想在用戶單擊按鈕后進行 href
這是我當前的代碼,但它不起作用。我點擊后,確認會出來,但我點擊后它不會進入PHadmin_approveHospital.php。
echo "<a href=\"PHadmin_approveHospital.php?id=".$row["HospitalID"]."\" onclick=\"return confirm('do you want to approve Y/N')\"><input type=\"submit\" value=\"Approve\"></a>";
全功能
public function displayAllHospital() {
$sql = "SELECT * FROM hospital";
$result = @mysqli_query($this->conn, $sql);
echo "<table class='table table-bordered'>";
echo "<thead>";
echo "<tr>";
echo "<th>ID # <i class='fa fa-sort'></i></th>";
echo "<th>Name </th>";
echo "<th>Email </th>";
echo "<th>Contact Number <i class='fa fa-sort'></i></th>";
echo "<th>Status </th>";
echo "<th>Actions</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
while($row = mysqli_fetch_assoc($result)){
echo "<tr>";
echo "<td>" . $row["HospitalID"] . "</td>";
echo "<td>" . $row["Hospitalname"] . "</td>" ;
echo "<td>" . $row["email"] . "</td>" ;
echo "<td>" . $row["contactno"] . "</td>" ;
echo "<td>" . $row["status"] . "</td>" ;
echo "<td>";
echo "<a href=\"PHadmin_editHospital.php?id=".$row["HospitalID"]."\" class='view' title='View' data-toggle='tooltip'><i class='material-icons'></i></a>";
echo "<a href=\"PHadmin_editHospital.php?id=".$row["HospitalID"]."\" class='edit' title='Edit' data-toggle='tooltip'><i class='material-icons'></i></a>";
echo "<a href=\"PHadmin_deleteHospital.php?id=".$row["HospitalID"]."\" onclick=\"return confirm('do you want to delete Y/N')\" class='delete' title='Delete' data-toggle='tooltip'><i class='material-icons'></i></a>";
echo "</td>";
echo "<td>";
if($row["status"] == "pending"){
echo "<a href=\"PHadmin_approveHospital.php?id=".$row["HospitalID"]."\" onclick=\"return confirm('do you want to approve Y/N')\"><input type=\"submit\" value=\"Approve\"></a>";
}
echo "</td>";
echo "</tr>";
echo "</tbody>";
echo "</form>";
echo "</tr>";
}
echo "</table>";
}
謝謝你的幫助。
uj5u.com熱心網友回復:
您可以在點擊按鈕時呼叫一個javascript函式,然后顯示確認資訊,以便用戶確認或不確認(如果確認,則跳轉到url)
您可以使用以下代碼:
<input type="button" value='Approve' onclick="javascript:check1();">
<script>
function check1() {
if(confirm("Do you want to approve?")) {
window.location.href="PHadmin_approveHospital.php?id=<?php echo $row["HospitalID"]. '\'; ?>";
}
}
</script>
因此,對于您更新的代碼,它將是:
<?php
public function displayAllHospital() {
echo '
<script>
function check1(var1) {
if(confirm("Sure to delete ?")) {
window.location.href="PHadmin_deleteHospital.php?id=" var1;
}
}
function check2(var2) {
if(confirm("Sure to approve ?")) {
window.location.href="PHadmin_approveHospital.php?id=" var2;
}
}
</script>';
$sql = "SELECT * FROM hospital";
$result = @mysqli_query($this->conn, $sql);
echo "<table class='table table-bordered'>";
echo "<thead>";
echo "<tr>";
echo "<th>ID # <i class='fa fa-sort'></i></th>";
echo "<th>Name </th>";
echo "<th>Email </th>";
echo "<th>Contact Number <i class='fa fa-sort'></i></th>";
echo "<th>Status </th>";
echo "<th>Actions</th>";
echo "</tr>";
echo "</thead>";
echo "<tbody>";
while($row = mysqli_fetch_assoc($result)){
echo "<tr>";
echo "<td>" . $row["HospitalID"] . "</td>";
echo "<td>" . $row["Hospitalname"] . "</td>" ;
echo "<td>" . $row["email"] . "</td>" ;
echo "<td>" . $row["contactno"] . "</td>" ;
echo "<td>" . $row["status"] . "</td>" ;
echo "<td>";
echo "<a href=\"PHadmin_editHospital.php?id=".$row["HospitalID"]."\" class='view' title='View' data-toggle='tooltip'><i class='material-icons'></i></a>";
echo "<a href=\"PHadmin_editHospital.php?id=".$row["HospitalID"]."\" class='edit' title='Edit' data-toggle='tooltip'><i class='material-icons'></i></a>";
echo "<input type=button value=Delete onclick='javascript:check1(". $row["HospitalID"] . ")';>";
echo "</td>";
echo "<td>";
if($row["status"] == "pending"){
echo "<input type=button value=Approve onclick='javascript:check2(". $row["HospitalID"] . ")';>";
}
echo "</td>";
echo "</tr>";
echo "</tbody>";
echo "</form>";
echo "</tr>";
}
echo "</table>";
}
?>
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