C -如何計算程式中得分最高的人

我正在開發一個程式，它允許用戶為足球比賽輸入一些姓名和整數，即輸入球員的姓名、球衣號碼和得分，然后在最后列印出來。

我將如何找到得分最高的球員的名字并列印出來？

這是我下面的不完整代碼：

void showHighest(Player p[], int size)
{
    int high = 0;

    for (int counter = 0; counter < size; counter  )
    {
        if (high < p[counter].points)
        {
            high = p[counter].points;
        }

        if (p[counter].points   )
        {

        }
    }
    cout << "The player with the most points was: " << p[high].name << "with " << high << "amount of points." << endl;
}

uj5u.com熱心網友回復：

您需要跟蹤陣列中最高玩家的索引，而不僅僅是最高點。在您的cout陳述中，您使用最高點就好像它是一個index，而事實并非如此。

試試這個：

void showHighest(Player p[], int size)
{
    int highest_points = 0;
    int highest_index = -1;

    for (int counter = 0; counter < size;   counter)
    {
        if (highest_points < p[counter].points)
        {
            highest_index = counter;
            highest_points = p[counter].points;
        }
    }

    if (highest_index != -1)
        cout << "The player with the most points was: " << p[highest_index].name << " with " << highest_points << " amount of points." << endl;
}

或者，您可以將跟蹤變數初始化為第一個玩家的資訊，并在第二個玩家處開始回圈，例如：

void showHighest(Player p[], int size)
{
    if (size < 1) return;

    int highest_points = p[0].points;
    int highest_index = 0;

    for (int counter = 1; counter < size;   counter)
    {
        if (highest_points < p[counter].points)
        {
            highest_index = counter;
            highest_points = p[counter].points;
        }
    }

    cout << "The player with the most points was: " << p[highest_index].name << " with " << highest_points << " amount of points." << endl;
}

或者，使用指標跟蹤Player最高的points，例如：

void showHighest(Player p[], int size)
{
    if (size < 1) return;

    Player* highest_player = &p[0];

    for (int counter = 1; counter < size;   counter)
    {
        if (highest_player->points < p[counter].points)
        {
            highest_player = &p[counter];
        }
    }

    cout << "The player with the most points was: " << highest_player->name << " with " << highest_player->points << " amount of points." << endl;
}

或者，您可以使用標準std::max_element()演算法Player在points不使用手動回圈的情況下找到最高的，例如：

#include <algorithm>

void showHighest(Player p[], int size)
{
    if (size < 1) return;

    auto p_end = p   size;
    auto it = std::max_element(p, p_end,
        [](const Player &a, const Player &b){
            return a.points < b.points;
        }
    );

    cout << "The player with the most points was: " << it->name << " with " << it->points << " amount of points." << endl;
}

uj5u.com熱心網友回復：

一個好的解決方案是將“高”整數的更改設定為玩家物件。然后，您將持有玩家物件，而不是僅持有最高分。

void showHighest(Player p[], int size)
{
    Player* high;

    for (int counter = 0; counter < size; counter  )
    {
        if (high.points < p[counter].points)
        {
            high = p[counter];
        }

    }
    cout << "The player with the most points was: " << high.name << "with " << high.points << "amount of points." << endl;
}

顯然，還有許多其他方法如上所述。另一種不太有效的方法是“記住”最高分值（就像你做的那樣），然后檢查哪個玩家有這個分數：

    void showHighest(Player p[], int size)
    {
        int high = 0;
    
        for (int counter = 0; counter < size; counter  )
        {
            if (high < p[counter].points)
            {
                high = p[counter].points;
            }
        }
        string name = "";
        for (int counter = 0; counter < size; counter   )
        {
          if(player[counter].points == high)
          {
             name = p[counter].name;
          }
        }
        cout << "The player with the most points was: " << name << "with" << high << "amount of points." << endl;
    }

你可以找到很多其他的方法。由于使用了您在 C 中的 OOP 優勢，我會推薦第一個。

標籤：C

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