我有一個陣列，我想在其中合并一個特定的索引。
["captain:", "robot", "alpha", "beta:", "gama", "delta:", "fighter", "test", "exp"]
這樣的想法，每個偶數元素都應該包含：而其余元素不應該包含：
我想要的輸出：
["captain:", "robot, alpha", "beta:", "gama", "delta:", "fighter, test, exp"]
考慮到陣列是可變的，例如，陣列可以是：
["captain:", "robot", "beta:", "game", "exp", "delta:", "fighter", "test"]
輸出應該是相同的，每個偶數都有 : 和奇數索引沒有 :
有人可以幫忙嗎？
uj5u.com熱心網友回復：
這是一個使用groupby：
import itertools
x = ["captain:", "robot", "alpha", "beta:", "gama", "delta:", "fighter", "test", "exp"]
new_list = []
for key, group in itertools.groupby(x, key = lambda string: string.endswith(':')):
if key: # in case you happen to consecutive values that end in a colon
new_list = list(group)
else: # these elements do not end in a colon
new_list.append(', '.join(group))
print(new_list)
# ['captain:', 'robot, alpha', 'beta:', 'gama', 'delta:', 'fighter, test, exp']
在這里，分組鍵檢查專案是否以 a 結尾":"，如果是，key是True，否則是False。如果 的連續值key相同，則將它們放在同一組中。因此，包含冒號的字串后面的任意數量的元素都將被組合在一起。
uj5u.com熱心網友回復：
itertools.groupby() 你覆寫了嗎？
lst = ["captain:", "robot", "alpha", "beta:", "gama", "delta:", "fighter", "test", "exp"]
print([', '.join(g[1]) for g in itertools.groupby(lst, lambda s: s.endswith(':'))])
# ['captain:', 'robot, alpha', 'beta:', 'gama', 'delta:', 'fighter, test, exp']
uj5u.com熱心網友回復：
我不知道 groupby 功能。因此，如果有人感興趣，這是一種替代方法：
sample = ["captain:", "robot", "alpha", "beta:", "gama", "delta:", "fighter", "test", "exp"]
def find_next_index(sample, start):
for i in range(len(sample)):
if i>start and ":" in sample[i]:
return i, ", ".join(sample[start 1:i]), False
return start, ", ".join(sample[start 1:]), True
result = []
start = 0
while True:
x,y,z = find_next_index(sample, start)
result.append(sample[start])
result.append(y)
start = x
if z:
break
print(result)
輸出：
['captain:', 'robot, alpha', 'beta:', 'gama', 'delta:', 'fighter, test, exp']
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