我想撰寫一個程式，可以幫助我使用 python 計算一些值。主要思想是我想制作一個表格，其中只有一半的單元格具有價值。（也就是說我要制作一個三角形）所以，我要制作的三角形就是這樣的格式。
12345
1234
123
12
1
但是，事情并沒有那么容易。請參閱下表。（也與圖1相同）
6.00 6.45 6.80 7.10 7.36 7.56 7.77
6.90 7.20 7.47 7.70 7.88 8.06
7.50 7.75 7.97 8.12 8.30
8.00 8.20 8.33 8.50
8.40 8.50 8.67
8.60 8.80
9.00
在上面的三角形中，每一行都是通過某個公式從前一行組成的。請參考圖2和圖3。
另外，請注意，在上面的三角形中，每個單元格都乘以 100。例如，左上角的 6.00 確實是 6% (0.06)。<< 請不要在我的程式中將數字乘以 100，因為這只是為了演示而發生的意外。
好的。所以，我想做一個程式，只要我輸入第一行，程式就會為我計算并顯示剩余的行。（這意味著顯示整個三角形）
下面是我的代碼。請看一看。我試圖寫一個框架，但是我遇到了兩個問題。
- 我不知道如何根據我在程式中輸入的第一個陣列（第一行）自動填充我的其他陣列（其他行）。
- 當我嘗試運行我的程式時，我不斷收到“IndexError：串列索引超出范圍”的錯誤。
這是我的代碼
array1 = [0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777] #This is the initial array that I input
array2 = [] #This should be the output after the first iteration, I hope that my programme can auto fill the remaining arrays (including this array) after I run my programme
array3 = [] #This is a blank array waiting for auto fill after I run my program
array4 = [] #This is a blank array waiting for auto fill after I run my program
array5 = [] #This is a blank array waiting for auto fill after I run my program
array6 = [] #This is a blank array waiting for auto fill after I run my program
array7 = [] #This is a blank array waiting for auto fill after I run my program
array8 = [] #This is a blank array waiting for auto fill after I run my program
r = 0 # Set the initial position for the table that I want to make, and this is similar to the x-asis. Please refer to picture 2.
s = 1 # Set the initial position for the table that I want to make, and this is similar to the y-asis. Please refer to picture 2.
def SpotRateForcast(i,j,k):
global r
global s
while (r <= len(k)): # I try to make the first loop here
s = 1 # Reset the value when the first row is completed such that the second loop can work in the second row
while (s <= len(k)): # this is the second loop to determine when to stop in the each row
x = ((((1 k[j - 1])**j) / ((1 k[i - 1])**i))**(1/(j-i))) - 1 #Calculate the value by the certain formula
print(("%.4f" % round(x,4)), end=' , ') #Print the value up to 4 decimal places
s = 1 #Record one value is calculated and done
SpotRateForcast(i,j 1,k) #Start to calculate and print the next value
r = 1 # Switch to the next row when the second loop is finished
SpotRateForcast(r,s,array1) #The code to run the program
感謝您閱讀我的問題。我想請人幫我完成這個程式。如您所見，我的編碼可能很糟糕，因為我是編程新手。但我已經盡了最大的努力去做我能做的一切。
我不介意您編輯我的代碼。如果你能為我寫一個新的代碼就更好了。我可以向你學習如何撰寫更好的代碼。
最后，我還有一個要求。請在您撰寫的代碼中添加許多注釋，否則我可能無法理解您寫的內容（我是初學者）。非常感謝你！
uj5u.com熱心網友回復：
你想多了。
如果您只需要列印一個三角形，只需按順序列印每一行，并為每一行按順序列印其值：
S = [0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]
n = len(S)
print(('{:0.4f} ' * n).format(*S)) # print initial line
for i in range(1,n): # loop over rows
for j in range(i 1, n 1): # then over colums
num = (1 S[j -1])**j
den = (1 S[i - 1])**i
x = (num/den)**(1/(j - i)) -1 # ok we have f(i, j)
print('{:0.4f}'.format(x), end=' ') # print it followed with a space
print('') # add a newline after a full row
它給：
0.0600 0.0645 0.0680 0.0710 0.0736 0.0756 0.0777
0.0690 0.0720 0.0747 0.0770 0.0787 0.0807
0.0750 0.0775 0.0797 0.0812 0.0830
0.0801 0.0821 0.0833 0.0850
0.0841 0.0849 0.0867
0.0857 0.0880
0.0904
現在，如果您想首先構建陣列，因為您稍后將對其進行后處理，只需將每個欄位值附加到該行的串列中，然后將每個串列附加到串列的全域串列中
S = [0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]
n = len(S)
result = [S] # add the initial row
for i in range(1,n): # loop over rows
row = [] # prepare a new list for the row
result.append(row) # and append it to result
for j in range(i 1, n 1): # then over colums
num = (1 S[j -1])**j
den = (1 S[i - 1])**i
x = (num/den)**(1/(j - i)) -1 # ok we have f(i, j)
row.append(x) # as a list is modifiable we can append to it
uj5u.com熱心網友回復：
array=[[0.06,0.0645,0.068,0.071,0.0736,0.0756,0.0777]]
n = len(array[0])
#outer loop
for i in range(1, n):
#append new row
array.append([])
for j in range(n-i):
#i dont understand your calculations but they'd stand
array[i][j] = #here
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