我正在使用http://xpatheval.apphb.com/這個網站，它運行良好，我只是遇到了代碼問題并獲得了我需要的價值。我在這里有一個 XML 代碼：
<?xml version="1.0"?>
<RIGA>
<STREET Name="Brivibas">
<HOUSE No="1">
<FLAT No="1">
<INHABITANT Year="1970" Gender="M">Ivanovs Sergejs</INHABITANT>
<INHABITANT Year="1970" Gender="F">Ivanova Anna</INHABITANT>
</FLAT>
<FLAT No="2">
<INHABITANT Year="1972" Gender="M">Strods Janis</INHABITANT>
<INHABITANT Year="1972" Gender="F">Strode Inna</INHABITANT>
<INHABITANT Year="1974" Gender="F">Strode Julija</INHABITANT>
</FLAT>
</HOUSE>
<HOUSE No="2">
<FLAT No="1">
<INHABITANT Year="1974" Gender="M">Zemzars Uldis</INHABITANT>
</FLAT>
</HOUSE>
</STREET>
<STREET Name="Elizabetes">
<HOUSE No="1">
<FLAT No="1">
<INHABITANT Year="1985" Gender="M">Celms Juris</INHABITANT>
</FLAT>
<FLAT No="2">
<INHABITANT Year="1988" Gender="M">Dmitrijevs Igors</INHABITANT>
<INHABITANT Year="1988" Gender="F">Dmitrijeva Svetlana</INHABITANT>
<INHABITANT Year="1989" Gender="F">Dmitrijeva Olga</INHABITANT>
<INHABITANT Year="1989" Gender="M">Dmitrijevs Pjotrs</INHABITANT>
</FLAT>
</HOUSE>
</STREET>
</RIGA>
我寫的 Xquery 代碼是這樣的：
<MALES>
{let $male:=//INHABITANT[@Gender="M"]
for $male in (1 to 6)
return <MALE>{$male}</MALE>}
</MALES>
我越來越：
<MALES>
<MALE>1</MALE>
<MALE>2</MALE>
<MALE>3</MALE>
<MALE>4</MALE>
<MALE>5</MALE>
<MALE>6</MALE>
</MALES>
但我需要的是：
<MALES>
<MALE>First Name Last Name</MALE>
<MALE>First Name Last Name</MALE>
<MALE>First Name Last Name</MALE>
<MALE>First Name Last Name</MALE>
<MALE>First Name Last Name</MALE>
<MALE>First Name Last Name</MALE>
</MALES>
我的代碼哪里出錯了？
我有 0 次使用 XML 和 Xquery 的經驗
uj5u.com熱心網友回復：
您需要將 XPath 運算式的文本節點系結到變數，而不是數字 1 到 6：
<MALES>{
for $male in //INHABITANT[@Gender = "M"]/text()
return <MALE>{ $male }</MALE>
}</MALES>
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