將資訊從一個串列添加到另一個串列

所以我有這兩個串列，一個包含城市，一個包含其他資訊串列。我想在第二個串列的每個串列的索引 0 中插入城市名稱。問題是最后我只有一個列印的城市名稱（最后一個）。有人可以幫我解決這個問題嗎？謝謝 ！

cities = ["Paris", "London", "New York"]

data = [
    ["", "", "", "", 1, 1, "Buildings"],
    ["", "", "", "", 2, 1, "Streets"],
    ["", "", "", "", 3, 1, "Avenues"],
    ["", "", "", "", 1, 2, "Buildings"],
    ["", "", "", "", 2, 2, "Streets"],
    ["", "", "", "", 3, 2, "Avenues"],
]

result = []
counter = -1
while counter != len(cities) - 1:
    counter  = 1
    number = -1
    while number != len(data) - 1:
        number  = 1
        data[number][0] = cities[counter]
        result.append(data[number])

print(result)

給我

result = [['New York', '', '', '', 1, 1, 'Buildings'], 
['New York', '', '', '', 2, 1, 'Streets'], 
['New York', '', '', '', 3, 1, 'Avenues'], 
['New York', '', '', '', 1, 2, 'Buildings'], 
['New York', '', '', '', 2, 2, 'Streets'], 
['New York', '', '', '', 3, 2, 'Avenues'], 
# (and so on)
]

而我寧愿有

result = [['New York', '', '', '', 1, 1, 'Buildings'], 
['Paris', '', '', '', 2, 1, 'Streets'], 
['Paris', '', '', '', 3, 1, 'Avenues'], 
['Paris', '', '', '', 1, 2, 'Buildings'], 
['Paris', '', '', '', 2, 2, 'Streets'], 
['Paris', '', '', '', 3, 2, 'Avenues'], 
['Paris', '', '', '', 1, 1, 'Buildings'], 
['London', '', '', '', 2, 1, 'Streets'], 
['London', '', '', '', 3, 1, 'Avenues'], 
['London', '', '', '', 1, 2, 'Buildings'], 
['London', '', '', '', 2, 2, 'Streets'], 
['London', '', '', '', 3, 2, 'Avenues'], 
['London', '', '', '', 1, 1, 'Buildings'], 
['New York', '', '', '', 2, 1, 'Streets'], 
['New York', '', '', '', 3, 1, 'Avenues'], 
['New York', '', '', '', 1, 2, 'Buildings'], 
['New York', '', '', '', 2, 2, 'Streets'], 
['New York', '', '', '', 3, 2, 'Avenues']
]

謝謝

uj5u.com熱心網友回復：

不要試圖從模板開始。Python 讓這很困難，因為你最終得到的是參考而不是副本。相反，像這樣構建它：

from pprint import pprint

cities = ["Paris", "London", "New York"]
layers = ['Buildings','Streets','Avenues']
data = []
for city in cities:
    for i in (1,2):
        for j,layer in enumerate(layers)
            data.append( [city, '', '', '', j 1, i, layer] )
pprint(data)

輸出：

[['Paris', '', '', '', 1, 1, 'Buildings'],
 ['Paris', '', '', '', 2, 1, 'Streets'],
 ['Paris', '', '', '', 3, 1, 'Avenues'],
 ['Paris', '', '', '', 1, 2, 'Buildings'],
 ['Paris', '', '', '', 2, 2, 'Streets'],
 ['Paris', '', '', '', 3, 2, 'Avenues'],
 ['London', '', '', '', 1, 1, 'Buildings'],
 ['London', '', '', '', 2, 1, 'Streets'],
 ['London', '', '', '', 3, 1, 'Avenues'],
 ['London', '', '', '', 1, 2, 'Buildings'],
 ['London', '', '', '', 2, 2, 'Streets'],
 ['London', '', '', '', 3, 2, 'Avenues'],
 ['New York', '', '', '', 1, 1, 'Buildings'],
 ['New York', '', '', '', 2, 1, 'Streets'],
 ['New York', '', '', '', 3, 1, 'Avenues'],
 ['New York', '', '', '', 1, 2, 'Buildings'],
 ['New York', '', '', '', 2, 2, 'Streets'],
 ['New York', '', '', '', 3, 2, 'Avenues']]

uj5u.com熱心網友回復：

以下是一些可以幫助您解決問題的代碼：

cities = ["Paris", "London", "New York"]

data = [
    ["", "", "", "", 1, 1, "Buildings"],
    ["", "", "", "", 2, 1, "Streets"],
    ["", "", "", "", 3, 1, "Avenues"],
    ["", "", "", "", 1, 2, "Buildings"],
    ["", "", "", "", 2, 2, "Streets"],
    ["", "", "", "", 3, 2, "Avenues"],
]

result = []
for i in cities:
  for j in data:
    result.append(j.copy()) #adding a copy of the list to result
    result[len(result) - 1][0] = i #editing the list we just added (the now last element in result) so the first element is the city

#printing the result
for i in result:
  print(i)

輸出：

['Paris', '', '', '', 1, 1, 'Buildings']
['Paris', '', '', '', 2, 1, 'Streets']
['Paris', '', '', '', 3, 1, 'Avenues']
['Paris', '', '', '', 1, 2, 'Buildings']
['Paris', '', '', '', 2, 2, 'Streets']
['Paris', '', '', '', 3, 2, 'Avenues']
['London', '', '', '', 1, 1, 'Buildings']
['London', '', '', '', 2, 1, 'Streets']
['London', '', '', '', 3, 1, 'Avenues']
['London', '', '', '', 1, 2, 'Buildings']
['London', '', '', '', 2, 2, 'Streets']
['London', '', '', '', 3, 2, 'Avenues']
['New York', '', '', '', 1, 1, 'Buildings']
['New York', '', '', '', 2, 1, 'Streets']
['New York', '', '', '', 3, 1, 'Avenues']
['New York', '', '', '', 1, 2, 'Buildings']
['New York', '', '', '', 2, 2, 'Streets']
['New York', '', '', '', 3, 2, 'Avenues']

這段代碼的作業方式是：

對于串列中的每個城市，我們首先在tocities中添加每個串列的副本，然后將第一個元素的值更改為城市。dataresult

我希望這有幫助！如果您需要任何進一步的幫助或澄清，請告訴我:)

uj5u.com熱心網友回復：

您可以使用list comprehension使用單行來執行此操作。

result = [[city]   el[1:] for el in data for city in cities]

這基本上是一個雙 for 回圈，我們迭代第一個中的城市 ( for city in cities)，然后對于每次迭代，我們迭代資料的元素 ( for el in data)。然后對于每次迭代，我們將城市連接到一個串列中 ([city]洗掉索引 0 處的條目的資料元素 ( el[:1])。在 Python 中，可以使用 .

我建議你學習處理串列的“Pythonic”方式，它會讓你的代碼更短更容易理解。

uj5u.com熱心網友回復：

這是你的答案

result_1 = []
result_2 = []
for cities_index, cities in enumerate(cities):
    for line_data in data:
        print(cities)
        line_1 = line_data.copy()
        line_1[0] = cities
        print(line_1)
        result_1.append(line_1)
    result_2.extend(result_1)
print(result_2)

標籤：Python python-3.x 列表

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