假設我們有一個文本檔案加載：
file = open('my_file.txt',mode='r')
stg = file.read()
此檔案包含一些非英文未知字符。這些字符可能有不同的形式，如á, ?,?等。如何提取這些字符及其在文本檔案中的位置？所以輸出是這些字符的串列及其位置（行號）。
uj5u.com熱心網友回復：
因此，假設您不想找到所有非 [english, number, punctuation, backslash] 字符，您可以使用以下代碼查找所有位置和數字
[(match.start(0), match.group()) for match in re.finditer(f'[^a-zA-Z0-9{string.punctuation}\\\]', stg)]
使用示例
ábxcsdas??????????????adasda/.1.32131.!#@%$%&*^()|\}}"?>:{}?><<"
它會回來
[(0, 'á'), (8, '?'), (9, '?'), (10, '?'), (11, '?'), (12, '?'), (13, '?'), (14, '?'), (15, '?'), (16, '?'), (17, '?'), (18, '?'), (19, '?'), (20, '?'), (21, '?')]
uj5u.com熱心網友回復：
這是我用于我的一個專案的代碼。它不檢查標點符號和特殊字符。
file = open('test.txt',mode='r')
lines = file.readlines()
def isEnglishChar(s):
try:
s.encode(encoding='utf-8').decode('ascii')
except UnicodeDecodeError:
return False
else:
return True
for index, value in enumerate(lines):
for i in range(0, len(value)):
bool = isEnglishChar(value[i])
if(not bool):
print (value[i], index 1)
uj5u.com熱心網友回復：
ASCII 字符的 Unicode 值介于 0 和 127 之間。任何 Unicode 值大于 127 的字符都不是 ASCII。
with open(filename) as fp:
for lineno, line in enumerate(fp, start=1):
for ch in line:
if ord(ch) > 127:
print(lineno, ch)
uj5u.com熱心網友回復：
with open("testfile.txt", 'w') as f_out:
test_text= '''
This file contains some non-English unknown characters.
These characters may have different forms like á,
?, ?, etc. How can I extract these characters with their location in the text file
'''
f_out.write(test_text)
with open("testfile.txt") as fp:
for lineno, line in enumerate(fp, start=1):
ch_count = 0
for ch in line:
ch_count = 1
if ord(ch) > 127:
print(f'{lineno=}\tCharacter Number={ch_count}\t {ch=}')
輸出
lineno=3 Character Number=52 ch='á'
lineno=4 Character Number=5 ch='?'
lineno=4 Character Number=8 ch='?'
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