一個小時以來一直試圖找出問題

此代碼應該給出一條錯誤訊息，“錯誤請重試！” 如果輸入的顏色不是紅色、藍色或黃色。它給了我錯誤訊息，同時也給了我正確的輸入，我不知道為什么。

ColorOne = input('Enter the first primary color please ')
ColorTwo = input('Enter the second primary color please ')
if ColorOne != ('red' or 'blue' or 'yellow'):
        print('Error please try again!')
if ColorTwo != ('red' or 'blue' or 'yellow'):
        print('Error please try again!')
if ColorOne == ('red') and ColorTwo == ('blue'):
        print('Purple')
if ColorOne == ('red') and ColorTwo == ('yellow'):
        print('Orange')
if ColorOne == ('blue') and ColorTwo == ('yellow'):
        print('Green')
if ColorTwo == ('red') and ColorOne == ('blue'):
        print('Purple')
if ColorTwo == ('red') and ColorOne == ('yellow'):
        print('Orange')
if ColorTwo == ('blue') and ColorOne == ('yellow'):
        print('Green')

uj5u.com熱心網友回復：

嘗試這個：

ColorOne = input('Enter the first primary color please ')
ColorTwo = input('Enter the second primary color please ')
if ColorOne not in ['red','blue','yellow']:
        print('Error please try again!')
if ColorTwo not in ['red','blue','yellow']:
        print('Error please try again!')
if ColorOne == ('red') and ColorTwo == ('blue'):
        print('Purple')
if ColorOne == ('red') and ColorTwo == ('yellow'):
        print('Orange')
if ColorOne == ('blue') and ColorTwo == ('yellow'):
        print('Green')
if ColorTwo == ('red') and ColorOne == ('blue'):
        print('Purple')
if ColorTwo == ('red') and ColorOne == ('yellow'):
        print('Orange')
if ColorTwo == ('blue') and ColorOne == ('yellow'):
        print('Green')

您的代碼的問題在于邏輯，在現實世界（口語）中，您會說如果顏色不是紅色、藍色或黃色，則執行某些操作，但在編程邏輯中，這不會像那樣作業。!= （紅色或藍色或黃色）等于如果顏色不是紅色而不是藍色而不是黃色，則執行某些操作。這就是使用德摩根定律。

uj5u.com熱心網友回復：

解決了。

ColorTwo = input('Enter the second primary color please ')
if ColorOne not in ('red', 'blue', 'yellow'):
        print('Error please try again!')
if ColorTwo not in ('red', 'blue', 'yellow'):
        print('Error please try again!')
if ColorOne == ('red') and ColorTwo == ('blue'):
        print('Purple')
if ColorOne == ('red') and ColorTwo == ('yellow'):
        print('Orange')
if ColorOne == ('blue') and ColorTwo == ('yellow'):
        print('Green')
if ColorTwo == ('red') and ColorOne == ('blue'):
        print('Purple')
if ColorTwo == ('red') and ColorOne == ('yellow'):
        print('Orange')
if ColorTwo == ('blue') and ColorOne == ('yellow'):
        print('Green')

你需要像這樣檢查

if ColorTwo not in ('red', 'blue', 'yellow'):

uj5u.com熱心網友回復：

問題是代碼ColorOne != ('red' or 'blue' or 'yellow'):。檢查變數是否是這些值之一不是正確的方法。你應該改為ColorOne not in ('red', 'blue', 'yellow'):

無論如何，我做了一些改進。

ColorOne = input('Enter the first primary color please ')
ColorTwo = input('Enter the second primary color please ')
    
Colors = ('red','blue','yellow')

combination = set((ColorOne.strip().lower(), ColorTwo.strip().lower()))

if not combination.issubset(Colors):
    print('Error please try again!')
elif combination == {'blue','red'}:
    print('Purple')
elif combination == {'red','yellow'}:
    print('Orange')
elif combination == {'blue','yellow'}:
    print('Green')

標籤：Python if 语句 输入

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