這是我的 script.sh：
emails=$(curl -X GET http://0.0.0.0:5000/v1/user/all | jq 'map(.[].email)')
echo $emails
for email in ${emails[@]}
do
echo $email
FROM=$(date "%Y-%m-%d %T")
TO=$(date -d "$today -1 month" " %Y-%m-%d %T")
SEND=true
JSON_STRING='{"email":"'"$email"'","from":"'"$FROM"'","to":"'"$TO"'","send":"'"$SEND"'"}'
curl -X POST http://0.0.0.0:5000/v1/invoice/print -d JSON_STRING
done
我從第一個 API 呼叫中獲得的電子郵件資料如下：
["[email protected]", "[email protected]", "[email protected]"]
API POST curl 執行此操作：
{"email":"[","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
{"email":""[email protected]",","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
{"email":""[email protected]",","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
{"email":""[email protected]",","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
{"email":"]","from":"2022-03-28 09:59:07","to":"2022-02-28 09:59:07","send":"true"}
{"message": "Internal Server Error"}
編輯：腳本回顯回傳：
["[email protected]", "[email protected]", "[email protected]"]
[
{"email":"[","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
"[email protected]",
{"email":""[email protected]",","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
"[email protected]",
{"email":""[email protected]",","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
"[email protected]",
{"email":""[email protected]",","from":"2022-03-28 09:59:06","to":"2022-02-28 09:59:06","send":"true"}
{"message": "Internal Server Error"}
]
{"email":"]","from":"2022-03-28 09:59:07","to":"2022-02-28 09:59:07","send":"true"}
{"message": "Internal Server Error"}
我不明白為什么電子郵件回圈處理括號 [ 和 ] 并回傳“[email protected]”，而不僅僅是“[email protected]”？我究竟做錯了什么？
uj5u.com熱心網友回復：
這是您從中獲得的輸出jq：
[
"[email protected]",
"[email protected]",
"[email protected]",
]
bash-wise，它不是一個陣列，它是一個多行字串。
對它進行索引不會[@]改變任何內容并回傳整個字串。迭代它for var in $multiline_string執行字串的每個空格分隔標記的代碼。由于您的電子郵件不包含空格，因此這是字串的每一行。
您需要jq生成一個以空格分隔的電子郵件地址串列，不帶引號，以便 bash 輕松處理它們。只需將您的 jq 命令更改為以下內容：
jq -r 'map(.[].email)[]'
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