有沒有辦法用回圈而不是21個if陳述句來減少這個計數？

我試圖在沒有 21 個 if 陳述句的情況下以更有效的方式運行此代碼。該程式確實需要兩個函式，main() 和counting()，并且輸出應該是“2”。這可以通過串列或任何其他更有效的方式來完成，同時保留這兩個功能嗎？上半場的所有常數都需要保持不變。每次我嘗試使用串列時都會出錯

def main():

    Word1 = "This"
    Word2 = "is"
    Word3 = "a"
    Word4 = "beautiful"
    Word5 = "and"
    Word6 = "sunny"
    Word7 = "day"
    Sentiment1 = "Beautiful"
    Sentiment2 = "beautiful"
    Sentiment3 = "sunny"
    

    #List = [Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3]
    count = counting(Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3)
    #List = [Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3]
    totalcount = counting(Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3)
    #print(count)
    print(totalcount)

def counting(Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3):
    count = 0
    if Word1 == Sentiment1:
        count = count   1
    if Word1 == Sentiment2:
        count = count  1
    if Word1 == Sentiment3:
        count = count  1
    if Word2 == Sentiment1:
        count = count   1
    if Word2 == Sentiment2:
        count = count  1
    if Word2 == Sentiment3:
        count = count  1
    if Word3 == Sentiment1:
        count = count   1
    if Word3 == Sentiment2:
        count = count  1
    if Word3 == Sentiment3:
        count = count  1
    if Word4 == Sentiment1:
        count = count   1
    if Word4 == Sentiment2:
        count = count  1
    if Word4 == Sentiment3:
        count = count  1
    if Word5 == Sentiment1:
        count = count   1
    if Word5 == Sentiment2:
        count = count  1
    if Word5 == Sentiment3:
        count = count  1
    if Word6 == Sentiment1:
        count = count   1
    if Word6 == Sentiment2:
        count = count  1
    if Word6 == Sentiment3:
        count = count  1
    if Word7 == Sentiment1:
        count = count   1
    if Word7 == Sentiment2:
        count = count  1
    if Word7 == Sentiment3:
        count = count  1  
        return(count)
            #if x == Sentiment2:
                #count = count  1
                #if x == Sentiment3:
                    #count = count   1

    #print(count)
    return(count)

main()
                    
    

我第二次嘗試使用串列和回圈：

def main():

    Word1 = "This"
    Word2 = "is"
    Word3 = "a"
    Word4 = "beautiful"
    Word5 = "and"
    Word6 = "sunny"
    Word7 = "day"
    Sentiment1 = "Beautiful"
    Sentiment2 = "beautiful"
    Sentiment3 = "sunny"

    List1 = [Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3]
    sentiment = [Sentiment1, Sentiment2, Sentiment3]
    counting = [Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3]
    #List = [Word1, Word2, Word3, Word4, Word5, Word6, Word7, Sentiment1, Sentiment2, Sentiment3]
    
    #print(totalcount)


    
    def counting():
            count = 0
            for sentiment in List1:
                    count = count   1

            #return(totalcount)


            

            #print(totalcount)
            print(count)
        

    counting() 
main()
                    
    

uj5u.com熱心網友回復：

words = [
    "This",
    "is",
    "a",
    "beautiful",
    "and",
    "sunny",
    "day"
]

sentiments = [
    "Beautiful",
    "beautiful",
    "sunny"
]


def counting(words, sentiments):
    return sum(1 for word in words if word in sentiments)

print(counting(words, sentiments))

uj5u.com熱心網友回復：

words = ["This", "is", "a", "beautiful", "and", "sunny", "day"]
sentiments = ["Beautiful", "beautiful", "sunny"]
count = 0

for word in words:
        count  = sentiments.count(word)

uj5u.com熱心網友回復：

這只是對已經呈現的內容的輕微變化。它利用了True在 sum 函式中計為 1 的事實。

def main():
    Word1 = "This"
    Word2 = "is"
    Word3 = "a"
    Word4 = "beautiful"
    Word5 = "and"
    Word6 = "sunny"
    Word7 = "day"
    Sentiment1 = "Beautiful"
    Sentiment2 = "beautiful"
    Sentiment3 = "sunny"

    words = [Word1, Word2, Word3, Word4, Word5, Word6, Word7]
    sentiments = [Sentiment1, Sentiment2, Sentiment3]
    count = counting(words, sentiments)
    print(count)

def counting(words, sentiments):
    return sum(w in sentiments for w in words)

main()

uj5u.com熱心網友回復：

結合兩個答案（創建最優雅的代碼）：

words = [
    "This",
    "is",
    "a",
    "beautiful",
    "and",
    "sunny",
    "day"
]

sentiments = [
    "Beautiful",
    "beautiful",
    "sunny"
]


def counting(words, sentiments):
    return sum(word in sentiments for word in words)

print(counting(words, sentiments))

標籤：Python if 语句

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