由于索引，Pythonpandas無法添加列名

這是我正在使用的資料框。

mtcars = pd.DataFrame.from_dict({'Unnamed: 0': {0: 'Mazda RX4', 1: 'Mazda RX4 Wag', 2: 'Datsun 710', 3: 'Hornet 4 Drive', 4: 'Hornet Sportabout', 5: 'Valiant', 6: 'Duster 360', 7: 'Merc 240D', 8: 'Merc 230', 9: 'Merc 280', 10: 'Merc 280C', 11: 'Merc 450SE', 12: 'Merc 450SL', 13: 'Merc 450SLC', 14: 'Cadillac Fleetwood', 15: 'Lincoln Continental', 16: 'Chrysler Imperial', 17: 'Fiat 128', 18: 'Honda Civic', 19: 'Toyota Corolla', 20: 'Toyota Corona', 21: 'Dodge Challenger', 22: 'AMC Javelin', 23: 'Camaro Z28', 24: 'Pontiac Firebird', 25: 'Fiat X1-9', 26: 'Porsche 914-2', 27: 'Lotus Europa', 28: 'Ford Pantera L', 29: 'Ferrari Dino', 30: 'Maserati Bora', 31: 'Volvo 142E'}, 'mpg': {0: 21.0, 1: 21.0, 2: 22.8, 3: 21.4, 4: 18.7, 5: 18.1, 6: 14.3, 7: 24.4, 8: 22.8, 9: 19.2, 10: 17.8, 11: 16.4, 12: 17.3, 13: 15.2, 14: 10.4, 15: 10.4, 16: 14.7, 17: 32.4, 18: 30.4, 19: 33.9, 20: 21.5, 21: 15.5, 22: 15.2, 23: 13.3, 24: 19.2, 25: 27.3, 26: 26.0, 27: 30.4, 28: 15.8, 29: 19.7, 30: 15.0, 31: 21.4}, 'cyl': {0: 6, 1: 6, 2: 4, 3: 6, 4: 8, 5: 6, 6: 8, 7: 4, 8: 4, 9: 6, 10: 6, 11: 8, 12: 8, 13: 8, 14: 8, 15: 8, 16: 8, 17: 4, 18: 4, 19: 4, 20: 4, 21: 8, 22: 8, 23: 8, 24: 8, 25: 4, 26: 4, 27: 4, 28: 8, 29: 6, 30: 8, 31: 4}, 'disp': {0: 160.0, 1: 160.0, 2: 108.0, 3: 258.0, 4: 360.0, 5: 225.0, 6: 360.0, 7: 146.7, 8: 140.8, 9: 167.6, 10: 167.6, 11: 275.8, 12: 275.8, 13: 275.8, 14: 472.0, 15: 460.0, 16: 440.0, 17: 78.7, 18: 75.7, 19: 71.1, 20: 120.1, 21: 318.0, 22: 304.0, 23: 350.0, 24: 400.0, 25: 79.0, 26: 120.3, 27: 95.1, 28: 351.0, 29: 145.0, 30: 301.0, 31: 121.0}, 'hp': {0: 110, 1: 110, 2: 93, 3: 110, 4: 175, 5: 105, 6: 245, 7: 62, 8: 95, 9: 123, 10: 123, 11: 180, 12: 180, 13: 180, 14: 205, 15: 215, 16: 230, 17: 66, 18: 52, 19: 65, 20: 97, 21: 150, 22: 150, 23: 245, 24: 175, 25: 66, 26: 91, 27: 113, 28: 264, 29: 175, 30: 335, 31: 109}, 'drat': {0: 3.9, 1: 3.9, 2: 3.85, 3: 3.08, 4: 3.15, 5: 2.76, 6: 3.21, 7: 3.69, 8: 3.92, 9: 3.92, 10: 3.92, 11: 3.07, 12: 3.07, 13: 3.07, 14: 2.93, 15: 3.0, 16: 3.23, 17: 4.08, 18: 4.93, 19: 4.22, 20: 3.7, 21: 2.76, 22: 3.15, 23: 3.73, 24: 3.08, 25: 4.08, 26: 4.43, 27: 3.77, 28: 4.22, 29: 3.62, 30: 3.54, 31: 4.11}, 'wt': {0: 2.62, 1: 2.875, 2: 2.32, 3: 3.215, 4: 3.44, 5: 3.46, 6: 3.57, 7: 3.19, 8: 3.15, 9: 3.44, 10: 3.44, 11: 4.07, 12: 3.73, 13: 3.78, 14: 5.25, 15: 5.424, 16: 5.345, 17: 2.2, 18: 1.615, 19: 1.835, 20: 2.465, 21: 3.52, 22: 3.435, 23: 3.84, 24: 3.845, 25: 1.935, 26: 2.14, 27: 1.513, 28: 3.17, 29: 2.77, 30: 3.57, 31: 2.78}, 'qsec': {0: 16.46, 1: 17.02, 2: 18.61, 3: 19.44, 4: 17.02, 5: 20.22, 6: 15.84, 7: 20.0, 8: 22.9, 9: 18.3, 10: 18.9, 11: 17.4, 12: 17.6, 13: 18.0, 14: 17.98, 15: 17.82, 16: 17.42, 17: 19.47, 18: 18.52, 19: 19.9, 20: 20.01, 21: 16.87, 22: 17.3, 23: 15.41, 24: 17.05, 25: 18.9, 26: 16.7, 27: 16.9, 28: 14.5, 29: 15.5, 30: 14.6, 31: 18.6}, 'vs': {0: 0, 1: 0, 2: 1, 3: 1, 4: 0, 5: 1, 6: 0, 7: 1, 8: 1, 9: 1, 10: 1, 11: 0, 12: 0, 13: 0, 14: 0, 15: 0, 16: 0, 17: 1, 18: 1, 19: 1, 20: 1, 21: 0, 22: 0, 23: 0, 24: 0, 25: 1, 26: 0, 27: 1, 28: 0, 29: 0, 30: 0, 31: 1}, 'am': {0: 1, 1: 1, 2: 1, 3: 0, 4: 0, 5: 0, 6: 0, 7: 0, 8: 0, 9: 0, 10: 0, 11: 0, 12: 0, 13: 0, 14: 0, 15: 0, 16: 0, 17: 1, 18: 1, 19: 1, 20: 0, 21: 0, 22: 0, 23: 0, 24: 0, 25: 1, 26: 1, 27: 1}}

)

當我輸入時mtcars.columns，我可以看到第一列是“未命名”。我正在嘗試添加列名。

Index(['Unnamed: 0', 'mpg', 'cyl', 'disp', 'hp', 'drat', 'wt', 'qsec', 'vs',
       'am', 'gear', 'carb'],
      dtype='object')

當我通過索引（索引為 0）呼叫列名時，我看到了同樣的情況

mtcars.columns[0]

我看到名字

'Unnamed: 0'

但是當我嘗試更改名稱時

mtcars.columns[0] = 'car'

我收到一個錯誤：

TypeError: Index does not support mutable operations

所以我想，也許它是一個索引列？

mtcars.Index

但我想這沒有任何意義，因為我看到了另一個錯誤。

AttributeError: 'DataFrame' object has no attribute 'Index'

在 R 中，您會執行類似的操作來更改列名（此代碼有效，但在 R 中）。

colnames(mtcars)[1] <- "new_name"

uj5u.com熱心網友回復：

你有幾個選擇：

mtcars = mtcars.rename(columns={mtcars.columns[0]: 'new'})

mtcars = mtcars.set_axis(['new'] list(mtcars.columns[1:]), axis=1)

# more "hacky" way, maybe not officially encouraged
# NB. in place modification
mtcars.columns.values[0] = 'new'

輸出：

                 new   mpg  cyl   disp   hp  drat     wt   qsec  vs   am
0          Mazda RX4  21.0    6  160.0  110  3.90  2.620  16.46   0  1.0
1      Mazda RX4 Wag  21.0    6  160.0  110  3.90  2.875  17.02   0  1.0
2         Datsun 710  22.8    4  108.0   93  3.85  2.320  18.61   1  1.0
3     Hornet 4 Drive  21.4    6  258.0  110  3.08  3.215  19.44   1  0.0
4  Hornet Sportabout  18.7    8  360.0  175  3.15  3.440  17.02   0  0.0

uj5u.com熱心網友回復：

如果所有其他方法都失敗并且您不記得更好的方法，那么像這樣明確列出所有列將始終有效：

mtcars.columns = ['car', 'mpg', 'cyl', 'disp', 'hp', 'drat', 'wt', 'qsec', 'vs', 'am', 'gear', 'carb']

uj5u.com熱心網友回復：

重命名列的方法如下：

mtcars.rename(columns={mtcars.columns[0]: 'car'}, inplace = True)
# This is equivalent to
mtcars = mtcars.rename(columns={mtcars.columns[0]: 'car'})

輸出：

                    car   mpg  cyl   disp   hp  drat     wt   qsec  vs   am
0             Mazda RX4  21.0    6  160.0  110  3.90  2.620  16.46   0  1.0
1         Mazda RX4 Wag  21.0    6  160.0  110  3.90  2.875  17.02   0  1.0
2            Datsun 710  22.8    4  108.0   93  3.85  2.320  18.61   1  1.0
3        Hornet 4 Drive  21.4    6  258.0  110  3.08  3.215  19.44   1  0.0
4     Hornet Sportabout  18.7    8  360.0  175  3.15  3.440  17.02   0  0.0
5               Valiant  18.1    6  225.0  105  2.76  3.460  20.22   1  0.0
6            Duster 360  14.3    8  360.0  245  3.21  3.570  15.84   0  0.0

標籤：Python 熊猫

上一篇：基于新資料框構建資料框

下一篇：想要為每次出現的列AppName更新列值，其中列值中的至少一個值是“是”st所有值都是“是”