我有兩個串列如下：
list1 <- list(c(`0` = 0L, `25` = 0L, `100` = 1L, `250` = 1L, `500` = 1L,
`1000` = 1L, Infinity = 3L), c(`0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L))
list2 <- list(c(`0` = 0L, `25` = 0L, `100` = 0L, `250` = 2L, `500` = 1L,
`1000` = 1L, Infinity = 3L), c(`0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L))
我想追加和追加list2[[1]]到. 以便：list1[[1]]list2[[2]]list1[[2]]
list_out <- list(c(`0` = 0L, `25` = 0L, `100` = 1L, `250` = 1L, `500` = 1L,
`1000` = 1L, Infinity = 3L, `0` = 0L, `25` = 0L, `100` = 0L, `250` = 2L, `500` = 1L,
`1000` = 1L, Infinity = 3L), c(`0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L, `0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L))
誰能幫我解釋我該怎么做？
uj5u.com熱心網友回復：
您可以使用lapply和c()。
lapply(1:length(list1), function(x) c(list1[[x]], list2[[x]]))
或或：mapply_appendc
mapply(append, list1, list2)
輸出
[[1]]
0 25 100 250 500 1000 Infinity 0
0 0 1 1 1 1 3 0
25 100 250 500 1000 Infinity
0 0 2 1 1 3
[[2]]
0 25 100 250 500 Infinity 0 25
0 0 1 1 1 4 0 0
100 250 500 Infinity
1 1 1 4
檢查它是否與您的相同list_out：
identical(lapply(1:length(list1), function(x) c(list1[[x]], list2[[x]])), list_out)
[1] TRUE
identical(mapply(append, list1, list2), list_out)
[1] TRUE
uj5u.com熱心網友回復：
這是另一個基礎 R 解決方案。
Map(c, list1, list2)
identical(Map(c, list1, list2), list_out)
#[1] TRUE
uj5u.com熱心網友回復：
另一種選擇是map2
library(purrr)
map2(list1, list2, c)
uj5u.com熱心網友回復：
您可以使用基本功能append：
> append(list1[[1]], list2[[1]])
0 25 100 250 500 1000 Infinity 0 25 100
0 0 1 1 1 1 3 0 0 0
250 500 1000 Infinity
2 1 1 3
> append(list1[[2]], list2[[2]])
0 25 100 250 500 Infinity 0 25 100 250
0 0 1 1 1 4 0 0 1 1
500 Infinity
1 4
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