我正在研究一些基本的基因編碼技術并遇到了一個問題：
我的字典應該是這樣的：
codon_dict= {
"A": {
"A": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"T": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"G": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"C": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
}
},
"T": {
"A": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"T": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"G": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"C": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
}
},
"G": {
"A": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"T": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"G": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"C": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
}
},
"C": {
"A": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"T": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"G": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
},
"C": {
"A": 0.0,
"T": 0.0,
"G": 0.0,
"C": 0.0
}
}
}
有沒有辦法從串列中構造它，而不是硬編碼？或遍歷for回圈并構造相同的？
那就是 code_dict["A"]["A"]["A"] 應該回傳我 0.0
uj5u.com熱心網友回復：
嘗試itertools.product：
from itertools import product
s = "ATGC"
out = {}
for x, y, z in product(s, repeat=3):
out.setdefault(x, {}).setdefault(y, {})[z] = 0.0
print(out)
印刷：
{
"A": {
"A": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"T": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"G": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"C": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
},
"T": {
"A": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"T": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"G": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"C": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
},
"G": {
"A": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"T": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"G": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"C": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
},
"C": {
"A": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"T": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"G": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
"C": {"A": 0.0, "T": 0.0, "G": 0.0, "C": 0.0},
},
}
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標籤：python-3.x 字典 嵌套的