我制作了 wordle，但我想讓它看起來更像官方的 wordle，所以我的最終目標是在每一行上制作 5 個 tkinter 條目，并將它們相互鏈接。當我運行此代碼時，底部的 mainloop 顯示為灰色，并且沒有出現任何視窗。
root = Tk()
root.geometry('400x400')
def testlen():
global textinentry1
textinentry1= entry1.get()
if len(textinentry1) >1 :
entry1.delete(0,END)
entry1.insert(0,textinentry1[0])
entry2.delete(0, END)
entry2.insert(0,textinentry1[1] )
entry1 = Entry(root,width=5, font = ('Georgia 18'), justify=CENTER)
entry1.grid(row=0, column=0)
entry2 = Entry(root, width=5, font = ('Georgia 18'), justify=CENTER)
entry2.grid(row=0, column=1)
entry3 = Entry(root, width = 5,font = ('Georgia 18'), justify=CENTER)
entry3.grid(row=0, column=2)
while True:
testlen()
root.mainloop()
我做錯什么了？
uj5u.com熱心網友回復：
在 while 回圈結束之后執行 永遠不會結束這mainloop是因為您在這里看不到視窗。
如果要運行此代碼，則可以使用該root.after()方法創建回圈。
from tkinter import *
root = Tk()
root.geometry('400x400')
def testlen():
global textinentry1
textinentry1= entry1.get()
if len(textinentry1) >1 :
entry2.delete(0, END)
entry2.insert(0,textinentry1[1] )
entry1 = Entry(root,width=22, font = ('Georgia 18'), justify=CENTER)
entry1.grid(row=0, column=0)
entry2 = Entry(root, width=22, font = ('Georgia 18'), justify=CENTER)
entry1button = Button(root, text="Enter", command = lambda :testlen())
entry1button.grid(row=1, column=0)
entry2.grid(row=2, column=0)
entry3 = Entry(root, width = 22,font = ('Georgia 18'), justify=CENTER)
entry3.grid(row=4, column=0)
def loop():
testlen()
root.after(1,loop) # 1 is 1 millisecond. Here root.after method call the loop function after 1 millisecond without crashing your code.
loop()
root.mainloop()
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