我是 Go 新手,我正在嘗試決議 XML 檔案。我不知道如何將下面的 xml 轉換為結構。我的 XML 檔案:
<profile>
<subsystem xmlns="urn:jboss:domain:logging:1.1">
<root-logger>
<level name="INFO"/>
<handlers>
<handler name="CONSOLE"/>
<handler name="FILE"/>
</handlers>
</root-logger>
</subsystem>
<subsystem xmlns="urn:jboss:domain:configadmin:1.0"/>
<subsystem xmlns="urn:jboss:domain:deployment-scanner:1.1">
<deployment-scanner path="deployments" relative-to="jboss.server.base.dir" scan-interval="5000"/>
</subsystem>
</profile>
uj5u.com熱心網友回復:
我的問題可以通過使用切片輕松解決。下面的代碼就是對應的結構體。
type Level struct {
Name string `xml:"name,attr"`
}
type Handler struct {
Name string `xml:"name,attr"`
}
type Handlers struct {
Handler []Handler `xml:"handler"`
}
type RootLogger struct {
Level Level `xml:"level"`
Handler Handlers `xml:"handlers"`
}
type DeploymentScanner struct {
Path string `xml:"path,attr"`
RelativeTo string `xml:"relative-to,attr"`
ScanInterval string `xml:"scan-interval,attr"`
}
type Subsystem struct {
XMLName xml.Name
RootLogger []RootLogger `xml:"root-logger"`
DeploymentScanner []DeploymentScanner `xml:"deployment-scanner"`
}
type Profile struct {
Subsystem []Subsystem `xml:"subsystem"`
}
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