如何使用這種風格的Bootstrap 5 在 Laravel 9 中創建分頁布局。
分頁布局
uj5u.com熱心網友回復：
你好我試著回答你的問題。在 laravel 9 中，也許您可??以嘗試使用此代碼并將其實施到您的專案中。
<?php
namespace App\Providers;
use Illuminate\Support\ServiceProvider;
use Illuminate\Pagination\Paginator;
class AppServiceProvider extends ServiceProvider
{
/**
* Register any application services.
*
* @return void
*/
public function register()
{
//
}
/**
* Bootstrap any application services.
*
* @return void
*/
public function boot()
{
Paginator::useBootstrap();
}
或者您可以在此鏈接中查看完整教程Laravel 9 Pagination Example with Bootstrap Tutorial 謝謝
uj5u.com熱心網友回復：
您可以發布分頁視圖。之后，您可以自定義它
php artisan vendor:publish --tag=laravel-pagination
資源/視圖/供應商/分頁/default.blade.php
@if ($paginator->hasPages())
<nav>
<ul class="pagination">
{{-- Previous Page Link --}}
@if ($paginator->onFirstPage())
<li class="disabled" aria-disabled="true" aria-label="@lang('pagination.previous')">
<span aria-hidden="true">‹</span>
</li>
@else
<li>
<a href="{{ $paginator->previousPageUrl() }}" rel="prev" aria-label="@lang('pagination.previous')">‹</a>
</li>
@endif
{{-- Pagination Elements --}}
@foreach ($elements as $element)
{{-- "Three Dots" Separator --}}
@if (is_string($element))
<li class="disabled" aria-disabled="true"><span>{{ $element }}</span></li>
@endif
{{-- Array Of Links --}}
@if (is_array($element))
@foreach ($element as $page => $url)
@if ($page == $paginator->currentPage())
<li class="active" aria-current="page"><span>{{ $page }}</span></li>
@else
<li><a href="{{ $url }}">{{ $page }}</a></li>
@endif
@endforeach
@endif
@endforeach
{{-- Next Page Link --}}
@if ($paginator->hasMorePages())
<li>
<a href="{{ $paginator->nextPageUrl() }}" rel="next" aria-label="@lang('pagination.next')">›</a>
</li>
@else
<li class="disabled" aria-disabled="true" aria-label="@lang('pagination.next')">
<span aria-hidden="true">›</span>
</li>
@endif
</ul>
</nav>
@endif
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標籤：php html 拉拉维尔 laravel-5 laravel-刀片