有一個程式每秒創建檔案。我想將檔案名附加到切片中并列印它們。現在我的程式執行不正確，它附加名稱但僅用于一個檔案名。所以我期望得到[]string{"1","2","3"}，而不是得到[]string{"1","1","1"}，[]string{"2","2","2"}, []string{"3","3","3"}。如何糾正我的 prog 以獲得預期的結果？
package main
import (
"encoding/csv"
"fmt"
"os"
"strconv"
"time"
)
func main() {
for {
time.Sleep(1 * time.Second)
createFile()
}
}
func createFile() {
rowFile := time.Now().Second()
fileName := strconv.Itoa(rowFile)
file, err := os.OpenFile(fileName, os.O_CREATE|os.O_WRONLY|os.O_APPEND, 0644)
if err != nil {
fmt.Println(err)
}
defer file.Close()
writer := csv.NewWriter(file)
writer.Comma = '|'
err = writer.Write([]string{""})
if err != nil {
fmt.Println(err)
}
countFiles(fileName)
}
func countFiles(fileName string) {
arrFiles := make([]string, 0, 3)
for i := 0; i < 3; i {
arrFiles = append(arrFiles, fileName)
}
fmt.Println(arrFiles)// here I expect ["1","2","3"] then ["4","5","6"] and so on. But now there is ["1","1","1"] then ["2","2","2"] and so on
}
uj5u.com熱心網友回復：
createFile()不會以任何方式保留創建的檔案名。你可以這樣做：
package main
import (
"encoding/csv"
"fmt"
"os"
"strconv"
"time"
)
func main() {
files := []string{}
for {
time.Sleep(1 * time.Second)
files = append(files, createFile())
fmt.Println(files)
}
}
func createFile() string {
rowFile := time.Now().Second()
fileName := strconv.Itoa(rowFile)
file, err := os.OpenFile(fileName, os.O_CREATE|os.O_WRONLY|os.O_APPEND, 0644)
if err != nil {
fmt.Println(err)
}
defer file.Close()
writer := csv.NewWriter(file)
writer.Comma = '|'
err = writer.Write([]string{""})
if err != nil {
fmt.Println(err)
}
return fileName
}
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