Python按多個動態鍵對字典串列進行排序，最后一個位置為無值

我想dict_list通過接收到的鍵串列 ( ) 對字典 ( ) 串列（也可以包含嵌套字典）進行排序groups。dicts 中的值通常可以是 None。

排序后，None值通常應放在最后一個位置。當我有以下組串列和字典串列時的示例

groups = ["key1", "key3.key4"]
dict_list = [
    {
        "key1": "abc",
        "key2": "def",
        "key3": {
            "key4": "ghi"
        },
        "key5": {
            "key6": "uvw"
        }
    }, 
    {
        "key1": "abc",
        "key2": "asd",
        "key3": {
            "key4": "abc"
        },
        "key5": {
            "key6": "uvw"
        }
    },    
    {
        "key1": None,
        "key2": "asd",
        "key3": {
            "key4": "abc"
        },
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": "abc",
        "key2": None,
        "key3": None,
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": "xyz",
        "key2": None,
        "key3": {
            "key4": "jklm"
        },
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": "abc",
        "key2": "dfd",
        "key3": {
            "key4": "ghi"
        },
        "key5": {
            "key6": "ers"
        }
    }
]

我希望得到以下輸出：

dict_list = [
    {
        "key1": "abc",
        "key2": "asd",
        "key3": {
            "key4": "abc"
        },
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": "abc",
        "key2": "def",
        "key3": {
            "key4": "ghi"
        },
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": "abc",
        "key2": "dfd",
        "key3": {
            "key4": "ghi"
        },
        "key5": {
            "key6": "ers"
        }
    },
    {
        "key1": "abc",
        "key2": None,
        "key3": None,
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": "xyz",
        "key2": None,
        "key3": {
            "key4": "jklm"
        },
        "key5": {
            "key6": "uvw"
        }
    },
    {
        "key1": None,
        "key2": "asd",
        "key3": {
            "key4": "abc"
        },
        "key5": {
            "key6": "uvw"
        }
    }
]

我嘗試使用 pythons 串列排序函式和 itertools.groupby 來實作這個，但我似乎無法理解它。

提前致謝！

uj5u.com熱心網友回復：

嘗試：

def get_values_from_dict(d, keys):
    out = []
    for k in keys:

        root = d
        for kk in k.split("."):
            root = root.get(kk)
            if not root:
                break

        out.append(root)

    return out


def key_function(lst):
    return [(v is None, v) for v in lst]


print(
    sorted(
        dict_list, key=lambda d: key_function(get_values_from_dict(d, groups))
    )
)

印刷：

[
    {
        "key1": "abc",
        "key2": "asd",
        "key3": {"key4": "abc"},
        "key5": {"key6": "uvw"},
    },
    {
        "key1": "abc",
        "key2": "def",
        "key3": {"key4": "ghi"},
        "key5": {"key6": "uvw"},
    },
    {
        "key1": "abc",
        "key2": "dfd",
        "key3": {"key4": "ghi"},
        "key5": {"key6": "ers"},
    },
    {"key1": "abc", "key2": None, "key3": None, "key5": {"key6": "uvw"}},
    {
        "key1": "xyz",
        "key2": None,
        "key3": {"key4": "jklm"},
        "key5": {"key6": "uvw"},
    },
    {
        "key1": None,
        "key2": "asd",
        "key3": {"key4": "abc"},
        "key5": {"key6": "uvw"},
    },
]

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