迭代嵌套字典并過濾特定欄位

我有一個混合了串列和字典的示例物件：

{
    "field_1" : "aaa",
    "field_2": [
        {
        "name" : "bbb",
          .....
        "field_4" : "ccc",
        "field_need_to_filter" : False,
        },

        {
        "name" : "ddd",
          .....
        "details": [
            {
            "name" : "eee",
            ....
            "details" : [
                {
                "name": "fff",
                .....
                "field_10": {
                    "field_11": "rrr",
                    ...
                    "details": [
                        {
                        "name": "xxx",
                        ...
                        "field_need_to_filter": True,
                        },
                        {
                        "name": "yyy",
                        ...
                        "field_need_to_filter": True,
                        },
                        {
                        "field_13": "zzz",
                        ...
                        "field_need_to_filter": False,
                        }
                                ]
                                }
                },


        ]}]}

       ]
}

我想迭代這個字典并為namewhere field_need_to_filteris添加所有相應的欄位True，所以對于這個例子，預期的輸出是： ["ddd.eee.fff.xxx", "ddd.eee.fff.yyy"]。我已經看這個太久了，我的大腦現在停止作業，任何幫助將不勝感激。謝謝。

uj5u.com熱心網友回復：

好的，我花了一些時間來考慮不同的情況并修復錯誤，但這有效（至少在您的 dict 示例中）；請注意，它假定包含 "field_need_to_filter": True 的字典是端點（該函式不會深入研究這些））。如果您需要，我很樂意為代碼添加解釋。

mydict = {
    "field_1" : "aaa",
    "field_2": [
        {
        "name" : "bbb",

        "field_4" : "ccc",
        "field_need_to_filter" : False,
        },

        {
        "name" : "ddd",

        "details": [
            {
            "name" : "eee",

            "details" : [
                {
                "name": "fff",

                "field_10": {
                    "field_11": "rrr",

                    "details": [
                        {
                        "name": "xxx",

                        "field_need_to_filter": True,
                        },
                        {
                        "name": "yyy",

                        "field_need_to_filter": True,
                        },
                        {
                        "field_13": "zzz",

                        "field_need_to_filter": False,
                        }
                                ]
                                }
                },


        ]}]}

       ]
}

def filter_paths(thing, path=''):
    if type(thing) == dict:
        # if this dict has a name, log it
        if thing.get("name"):
            path  = ('.' if path else '')    thing["name"]
        # if this dict has "...filter": True, we've reached an end point, and return the path
        if thing.get("field_need_to_filter") and thing["field_need_to_filter"]:
            return [path]
        # else we delve deeper
        result = []
        for key in thing:
            result  = [deep_path for deep_path in filter_paths(thing[key], path)]
        return result
    
    # if the current object is a list, we simply delve deeper
    elif type(thing) == list:
        result = []
        for element in thing:
            result  = [deep_path for deep_path in filter_paths(element, path)]
        return result

    # We've reached a dead-end, so we return an empty list
    else:
        return []
        
filter_paths(mydict)
# Out[204]: ['ddd.eee.fff.xxx', 'ddd.eee.fff.yyy']

uj5u.com熱心網友回復：

如果這是您的正確代碼，則在檢查 ddd 的欄位名稱后呼叫 iterate_fun 而不是 iterate_func

標籤：Python列表字典递归嵌套循环

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