// A complete working C program to demonstrate
// all insertion methods on Linked List
#include <bits/stdc .h>
using namespace std;
// A linked list node
class Node
{
public:
int data;
Node *next;
};
/* Given a reference (pointer to pointer)
to the head of a list and an int, inserts
a new node on the front of the list. */
void push(Node** head_ref, int new_data)
{
/* 1. allocate node */
Node* new_node = new Node();
/* 2. put in the data */
new_node->data = new_data;
/* 3. Make next of new node as head */
new_node->next = (*head_ref);
/* 4. move the head to point to the new node */
(*head_ref) = new_node;
}
/* Given a node prev_node, insert a new node after the given
prev_node */
void insertAfter(Node* prev_node, int new_data)
{
/*1. check if the given prev_node is NULL */
if (prev_node == NULL)
{
cout<<"The given previous node cannot be NULL";
return;
}
/* 2. allocate new node */
Node* new_node = new Node();
/* 3. put in the data */
new_node->data = new_data;
/* 4. Make next of new node as next of prev_node */
new_node->next = prev_node->next;
/* 5. move the next of prev_node as new_node */
prev_node->next = new_node;
}
/* Given a reference (pointer to pointer) to the head
of a list and an int, appends a new node at the end */
void append(Node** head_ref, int new_data)
{
/* 1. allocate node */
Node* new_node = new Node();
Node *last = *head_ref; /* used in step 5*/
/* 2. put in the data */
new_node->data = new_data;
/* 3. This new node is going to be
the last node, so make next of
it as NULL*/
new_node->next = NULL;
/* 4. If the Linked List is empty,
then make the new node as head */
if (*head_ref == NULL)
{
*head_ref = new_node;
return;
}
/* 5. Else traverse till the last node */
while (last->next != NULL)
{
last = last->next;
}
/* 6. Change the next of last node */
last->next = new_node;
return;
}
// This function prints contents of
// linked list starting from head
void printList(Node *node)
{
while (node != NULL)
{
cout<<" "<<node->data;
node = node->next;
}
}
/* Driver code*/
int main()
{
/* Start with the empty list */
Node* head = NULL;
// Insert 6. So linked list becomes 6->NULL
append(&head, 6);
// Insert 7 at the beginning.
// So linked list becomes 7->6->NULL
push(&head, 7);
// Insert 1 at the beginning.
// So linked list becomes 1->7->6->NULL
push(&head, 1);
// Insert 4 at the end. So
// linked list becomes 1->7->6->4->NULL
append(&head, 4);
// Insert 8, after 7. So linked
// list becomes 1->7->8->6->4->NULL
insertAfter(head->next, 8);
cout<<"Created Linked list is: ";
printList(head);
return 0;
}
// from geeksforgeek
為什么 append 和 push 函式有一個指向指標的指標(head_ref),而 insertAfter 函式有一個普通的指標(prev_node)?由于我們正在更改它們是頭節點還是前一個節點,因此應該是相同的方法(指標型別)。
我可以使用普通指標而不是指向指標的指標嗎?
uj5u.com熱心網友回復:
函式push和append兩者都需要能夠改變指向頭節點的指標。
如果他們只傳遞一個Node*指向頭的指標,那么他們將只能將該指標的本地副本更改為指向頭節點。但是,他們需要能夠改變指向頭節點的原始指標,也就是head函式中的變數main。這就是為什么他們需要一個指向head函式中變數的指標main,所以兩個函式都需要傳遞一個Node**.
與函式pushand 相比append,函式insertAfter永遠不需要更改傳遞給函式的指標。這就是為什么通過Node*.
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