根據物件id更新串列中的物件

我想知道是否可以通過其 id 直接更新 List 中的物件。這是我的物件結構：

public class MyObject {
    public UUID uuid;
    public String string1;
    public int int1;
    ...
}

在另一個物件中，我有一個 MyObject 串列，我想通過物件 ID 更新其中一個。除了以下代碼之外還有其他解決方案嗎？

List<MyObject> list = new ArrayList<>();
// Add many object into my list
MyObject newObject = new MyObject(...);

list.removeIf(o -> o.getUuid().equals(newObject.getUuid()));
list.add(newObject);

uj5u.com熱心網友回復：

如果您真的想堅持使用List.

List<MyObject> list = new ArrayList<>();
for (int i = 0; i < list.size(), i  ) {
    if (list.get(i).getUuid().equals(newObject.getUuid())) {
        list.set(i, newObject());
        // Probably want to stop the loop here.
    }
}

使用UUID作為一個關鍵Map使得它更簡單。

List<MyObject> list = new ArrayList<>();
Map<UUID, MyObject> map = list.stream().collect(Collecotrs.toMap(o -> o.getUuid(), o -> o));
map.put(newObject.getUuid(), newObject);
list = new ArrayList<>(map.values());

uj5u.com熱心網友回復：

緊湊，但hacky...

List<MyObject> list2 =
list.stream().map(item->item.getUuid().equals(newObject.getUuid()) ? newObject : item)
.collect(Collectors.toList();

uj5u.com熱心網友回復：

我認為最簡單的方法是以這樣一種方式實作哈希碼/等于，它會以 UUID 為目標。呼叫 add() 和 remove() 時，將在串列中添加和洗掉與 UUID 匹配的物件。

下面是一個例子：

import java.util.ArrayList;
import java.util.List;
import java.util.Objects;
import java.util.UUID;

public class ListExample {
    public static void main(String[] args) {
        List<MyObject> list = new ArrayList<>();
        list.add(new MyObject(UUID.fromString("299971c6-31b8-11ec-8d3d-0242ac130003"), "A", 0));
        list.add(new MyObject(UUID.fromString("31e77904-31b8-11ec-8d3d-0242ac130003"), "B", 1));
        list.add(new MyObject(UUID.fromString("368b0214-31b8-11ec-8d3d-0242ac130003"), "C", 2));
        System.out.println(list);
        list.remove(new MyObject(UUID.fromString("368b0214-31b8-11ec-8d3d-0242ac130003")));
        System.out.println(list);
        list.add(new MyObject(UUID.fromString("9b21edea-31b9-11ec-8d3d-0242ac130003"), "D", 3));
        System.out.println(list);
    }

    public static class MyObject {
        public UUID uuid;
        public String string1;
        public int int1;

        public MyObject(UUID uuid) {
            this.uuid = uuid;
        }

        public MyObject(UUID uuid, String string1, int int1) {
            this.uuid = uuid;
            this.string1 = string1;
            this.int1 = int1;
        }

        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;
            MyObject myObject = (MyObject) o;
            return Objects.equals(uuid, myObject.uuid);
        }

        @Override
        public int hashCode() {
            return Objects.hash(uuid);
        }

        @Override
        public String toString() {
            return "MyObject{"  
                "uuid="   uuid  
                ", string1='"   string1   '\''  
                ", int1="   int1  
                '}';
        }
    }

}

這是輸出：

[MyObject{uuid=299971c6-31b8-11ec-8d3d-0242ac130003, string1='A', int1=0}, MyObject{uuid=31e77904-31b8-11ec-8d3d-0242ac130003, string1='B', int1=1}, MyObject{uuid=368b0214-31b8-11ec-8d3d-0242ac130003, string1='C', int1=2}]
[MyObject{uuid=299971c6-31b8-11ec-8d3d-0242ac130003, string1='A', int1=0}, MyObject{uuid=31e77904-31b8-11ec-8d3d-0242ac130003, string1='B', int1=1}]
[MyObject{uuid=299971c6-31b8-11ec-8d3d-0242ac130003, string1='A', int1=0}, MyObject{uuid=31e77904-31b8-11ec-8d3d-0242ac130003, string1='B', int1=1}, MyObject{uuid=9b21edea-31b9-11ec-8d3d-0242ac130003, string1='D', int1=3}]

uj5u.com熱心網友回復：

使用這樣的東西：

    List<MyObject> list = new ArrayList<MyObject>();
    
    int id = 4; //the UUID of the Object you are searching for
    
    MyObject found = list.stream()
            .filter(MyObject -> (MyObject.getUUID()==id))
            .findAny()
            .orElse(null);
    
    int i = list.indexOf(found);
    int newUUID = 3;
    list.get(i).setUUID(newUUID);

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