JavaArrayListremoveAll-有解無憂

我正在研究一個虛擬醫院資料庫。我有一個ArrayList醫生理論上可以預約的所有可能時間的組合，以及另一個ArrayList持有實際注冊預約的時間。

Availability {
  int doctorid;
  String specialty;
  Date date;
  int order_of_appointment;
}
//////////

ArrayList<Availability> allTimes;

ArrayList<Availability> busyTimes;

我想要完成的是找到醫生有空的時間。這是 (allTimes - busyTimes) 的結果

我嘗試使用allTimes.removeAll(busyTimes)但它沒有洗掉任何內容。

我確保我覆寫了類中的 equals() 方法，Availability但它仍然沒有洗掉任何東西。

@Override
public boolean equals(Object o) {
  if (this == o) return true;
  if (!(o instanceof Availability)) return false;   
  Availability that = (Availability) o;
  return doctorid == that.doctorid &&
      order_of_appointment == that.order_of_appointment &&
      Objects.equals(specialty, that.specialty) &&
      Objects.equals(date, that.date);
}

輸出：

busyTimes = [Availability {doctorid=1, special='internal Medicine', date=2021-11-02, order_of_appointment=2}]
allTimes = [Availability{doctorid=1, special='internal Medicine', date=2021-11-02, order_of_appointment=1} , Availability{doctorid=1, special='internal Medicine', date=2021-11-02, order_of_appointment=2} , 可用性{doctorid=1, special='internal Medicine', date=2021-11-02, order_of_appointment=3}]
我為freeTimes獲得的輸出與allTimes相同，即使我希望它洗掉 order_of_appointment==2 的約會。

我對可能導致這種情況的原因完全一無所知。任何幫助，將不勝感激。提前致謝！

uj5u.com熱心網友回復：

你沒有展示你是如何創建陣列的，或者你是如何添加元素的。

我用 ArrayLists 做了一個簡單的程式并按預期作業：

import java.util.*;

class A {
  int id;
  A(int id) {
    this.id = id;
  }

  @Override
  public boolean equals(Object o) {
    return o instanceof A && this.id == ((A)o).id;
  }
  public String toString() {
    return String.format("A{id:%s}", id);
  }

  public static void main(String ... args) {
    List<A> a = new ArrayList<A>(Arrays.asList(new A(1), new A(2)));
    List<A> b = new ArrayList<A>(Arrays.asList(new A(2), new A(3)));
    a.removeAll(b);
    System.out.println(a);
  }
}

輸出：

[A{id:1}]

uj5u.com熱心網友回復：

錯誤的是，即使我將日期格式設定為“yyyy-MM-dd”，它仍然將時間存盤在 Date 物件中。我將 Date 物件轉換為字串，然后比較這些字串并且有效。謝謝你們。

uj5u.com熱心網友回復：

您需要使用比較邏輯覆寫Availability 類中的equals(Object obj) 方法。

我實施了它。請檢查。

import java.util.Date;

public class Availability {

    private int doctorId;
    private String specialty;
    private Date date;
    private int orderOfAppointment;

    public Availability() {
        super();        
    }

    public Availability(int doctorId, String specialty, Date date, int orderOfAppointment) {
        super();
        this.doctorId = doctorId;
        this.specialty = specialty;
        this.date = date;
        this.orderOfAppointment = orderOfAppointment;
    }

    public int getDoctorId() {
        return doctorId;
    }

    public void setDoctorId(int doctorId) {
        this.doctorId = doctorId;
    }

    public String getSpecialty() {
        return specialty;
    }

    public void setSpecialty(String specialty) {
        this.specialty = specialty;
    }

    public Date getDate() {
        return date;
    }

    public void setDate(Date date) {
        this.date = date;
    }

    public int getOrderOfAppointment() {
        return orderOfAppointment;
    }

    public void setOrderOfAppointment(int orderOfAppointment) {
        this.orderOfAppointment = orderOfAppointment;
    }

    @Override
    public String toString() {
        return "Availability  [doctorId="   doctorId   ", specialty="   specialty   ", date="   date
                  ", orderOfAppointment="   orderOfAppointment   "]";
    }

    @Override
    public boolean equals(Object obj) {
        boolean returnVal = false;
        Availability busyslote = (Availability) obj;
        if (this.doctorId == busyslote.doctorId && this.orderOfAppointment == busyslote.orderOfAppointment
                && this.specialty.equalsIgnoreCase(busyslote.specialty) && this.date.equals(busyslote.date)) {
            returnVal = true;
        } else {
            returnVal = false;
        }

        return returnVal;
    }
}

import java.util.ArrayList;
import java.util.Date;
import java.util.List;

public class AppointmentMain {

    public static void main(String[] args) {

        List<Availability> allAppointment = new ArrayList<>();
        List<Availability> attenedAppointment = new ArrayList<>();

        Availability obj1 = new Availability(1, "Internal Medicine", new Date(), 1);
        Availability obj2 = new Availability(1, "Internal Medicine", new Date(), 2);
        Availability obj3 = new Availability(1, "Internal Medicine", new Date(), 3);

        allAppointment.add(obj1);
        allAppointment.add(obj2);
        allAppointment.add(obj3);

        Availability obj4 = new Availability(1, "Internal Medicine", new Date(), 3);

        attenedAppointment.add(obj4);

        System.out.println("Befour count :"   allAppointment.size());
        allAppointment.removeAll(attenedAppointment);
        System.out.println("After count :"   allAppointment.size());
    }
}

轉載請註明出處，本文鏈接：https://www.uj5u.com/qukuanlian/347889.html

標籤：爪哇数组目的数组列表

上一篇：在映射器函式中具有正確型別縮小的映射物件

下一篇：JavaScript中的遞回問題有問題。基于物件陣列創建物件樹