有沒有人知道如何修改此腳本，以便每次找到特定單詞時都遍歷鍵值
word_replacement = {'rat':['pat', 'grey', 'squeeky']}
with open("main.txt") as main:
words = main.read().split()
replaced = []
for y in words:
replacement = word_replacement.get(y, y)
replaced.append(replacement)
text = ' '.join(replaced)
print (text)
new_main = open("main.txt", 'w')
new_main.write(text)
new_main.close()
樣本輸入：
rat went to the rat park to play with rat friends at the rat party
所需的輸出：
pat went to the grey park to play with squeeky friends at the pat party
uj5u.com熱心網友回復：
當您獲得給定單詞的字典條目時，您需要將其值作為串列進行處理，并選擇該串列中的一項作為原始單詞的替代品（而不是附加整個串列）。每次使用串列中的專案時，都應將其移到末尾，以便下一次出現的關鍵字使用不同的替換詞：
word_replacement = {'rat':['pat', 'grey', 'squeeky']}
words = "rat went to the rat park to play with rat friends at the rat party".split()
replaced = []
for y in words:
replacements = word_replacement.get(y) # get replacement list
if replacements: # if there is one, change y
y = replacements.pop(0) # use first replacement word
replacements.append(y) # and move it to the end of the list
replaced.append(y) # add original or replaced word
text = ' '.join(replaced)
print (text)
pat went to the grey park to play with squeeky friends at the pat party
uj5u.com熱心網友回復：
replace_idx = 0
for i, y in enumerate(words):
if y in word_replacement:
words[i] = word_replacement[y][replace_idx]
replace_idx = (replace_idx 1)%3
text = ' '.join(words)
print(text)
這將替換單詞而不創建新的單詞串列。此外，它適用于更大的 word_replacements 字典。
uj5u.com熱心網友回復：
最簡單的方法是擁有一個計數器并在您更換它時增加它。我不知道您的實際word_replacementdict 的那種形式，但您可能想要保存多個計數器，每個計數器都用于跟蹤不同的單詞。
word_replacement = {'rat':['pat', 'grey', 'squeeky']}
with open("main.txt") as main:
words = main.read().split()
replaced = []
counter_for_rat = 0 # This is your counter
for y in words:
n = word_replacement.get(y) # Return None if word not in word_replacement
if n is not None:
n = n[counter_for_rat % len(n)] # This prevents index out of range
counter_for_rat = 1
else:
n = y
replaced.append(n)
text = ' '.join(replaced)
print (text)
new_main = open("main.txt", 'w')
new_main.write(text)
new_main.close()
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