我如何使用我的輔助函式來獲得正確的輸出

所以我創建了一個輔助函式來幫助我的主要函式從字典中提取內容......這是我的代碼和函式

def rdict(recipes):
    recipes_splitted = {}
    for r in recipes:
        recipe_name, parts = r.split(":")
        recipe_parts = {}
        for part in parts.split(','):
            product, number = part.split('*')
            recipe_parts[product] = int(number)
        recipes_splitted[recipe_name] = recipe_parts
    return recipes_splitted
def extract(recipes, data):
    result = []
    for r in recipes:
        tmp = []
        for key in data[r]:
            tmp.append(f"{key}:{data[r][key]}")
        final_string = ""
        for i in range(len(tmp)):
            if i < len(tmp) - 1:
                final_string  = tmp[i]   ", "
            else:
                final_string  = tmp[i]
        result.append(final_string)
    return result

那么我現在要做的是確保data在extract(recipe, data)旅途中通過rdict(data)以來RDICT將資料轉換成一本字典，這正是我需要的。但是，當我試圖做for key in rdict(data[r]):輸出的回報Error. String is not supscriptable..

我應該怎么做才能成功實施更改？

編輯

所以從我當前的代碼來看，這是一個示例輸入..

print(extract(recipes = ['T-Bone', 'Green Salad1'],data = ["Pork Stew:Cabbage*5,Carrot*1,Fatty Pork*10",
"Green Salad1:Cabbage*10,Carrot*2,Pineapple*5",
"T-Bone:Carrot*2,Steak Meat*1"]
))

為了讓我的代碼作業，它必須是這樣的

print(extract(recipes = ['T-Bone', 'Green Salad1'], data = {'Pork Stew': {'Cabbage': 5, 'Carrot': 1, 'Fatty Pork': 10}, 'Green Salad1': {'Cabbage': 10, 'Carrot': 2, 'Pineapple': 5},'T-Bone': {'Carrot': 2, 'Steak Meat': 1}}))

所以從輸入中，資料應該從

data = ["Pork Stew:Cabbage*5,Carrot*1,Fatty Pork*10",
    "Green Salad1:Cabbage*10,Carrot*2,Pineapple*5",
    "T-Bone:Carrot*2,Steak Meat*1"]

到

data = {'Pork Stew': {'Cabbage': 5, 'Carrot': 1, 'Fatty Pork': 10}, 'Green Salad1': {'Cabbage': 10, 'Carrot': 2, 'Pineapple': 5},'T-Bone': {'Carrot': 2, 'Steak Meat': 1}}

uj5u.com熱心網友回復：

在extract()中將資料轉換為dict。

recipes = ['T-Bone', 'Green Salad1']

data = ["Pork Stew:Cabbage*5,Carrot*1,Fatty Pork*10",
"Green Salad1:Cabbage*10,Carrot*2,Pineapple*5",
"T-Bone:Carrot*2,Steak Meat*1"]


def rdict(recipes):
    recipes_splitted = {}
    for r in recipes:
        recipe_name, parts = r.split(":")
        recipe_parts = {}
        for part in parts.split(','):
            product, number = part.split('*')
            recipe_parts[product] = int(number)
        recipes_splitted[recipe_name] = recipe_parts
    return recipes_splitted


def extract(recipes, data):
    data = rdict(data)  # convert data to dict first
    result = []
    for r in recipes:
        tmp = []
        for key in data[r]:            
            tmp.append(f"{key}:{data[r][key]}")
        final_string = ""
        for i in range(len(tmp)):
            if i < len(tmp) - 1:
                final_string  = tmp[i]   ", "
            else:
                final_string  = tmp[i]
        result.append(final_string)
    return result

print(extract(recipes, data))

輸出：

['Carrot:2, Steak Meat:1', 'Cabbage:10, Carrot:2, Pineapple:5']

uj5u.com熱心網友回復：

1. 重命名rdict為parse_recipe，并將其修改為回傳一個更輕且更易于處理的元組

2. 摘錄：

   a) 建立一個食譜字典： data_recipes

   b）以獲得想要的菜譜，用防失蹤配方保護（內置結果這是一個空的字典：{}）

def parse_recipe(s):
    recipe, ings_s = s.split(':')
    ings_l = ings_s.split(',')
    
    ings_d= {}
    for ing in ings_l:
        i,q = ing.split('*')
        ings_d[i.strip()] = q.strip()

    return recipe.strip(), ings_d


def extract(recipes, data):
    data_recipes = {}
    for s in data:
        recipe, ings_d = parse_recipe(s)
        data_recipes[recipe] = ings_d

    return {r: data_recipes.get(r, dict()) for r in recipes}

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