在 Python 中轉換為字串表示的字典后，我希望根據特定值編輯一些鍵名。這是字串格式的字典示例：
s = '{"some.info": "ABC","more.info": "DEF","device.0.Id":"12345678", "device.0.Type":"DEVICE-X", ' \
'"device.0.Status":"ACTIVE", "device.1.Id":"123EFEF8", "device.1.Type":"DEVICE-Y", "device.1.Status":"NOT FOUND", ' \
'"device.2.Id":"ABCD4328", "device.2.Type":"DEVICE-Z", "device.2.Status":"SLEEPING", "other.info":"Hello", ' \
'"additional.info":"Hi Again",}'
我在下面有一個作業方法，它將字串轉換為字典，掃描包含 '.Type' 的關鍵條目，并將要替換的關鍵部分的元組放入串列中，并用什么來替換它。然而整個程序似乎效率太低，有沒有更好的方法來做到這一點？
我的字典中有感興趣的鍵值對，如下所示：
'device.0.Type':'DEVICE-X'
'device.1.Type':'DEVICE-Y'
'device.2.Type':'DEVICE-Z'
我想要做的是將 device.X 的所有 Key name 實體更改為 key 'device.X.Type' 的值。
例如：
'device.0.Id':'12345678', 'device.0.Type':'DEVICE-X', 'device.0.Status':'ACTIVE',
'device.1.Id':'123EFEF8', 'device.1.Type':'DEVICE-Y', 'device.1.Status':'NOT FOUND', etc
會成為：
'DEVICE-X.Id':'12345678', 'DEVICE-X.Type':'DEVICE-X', 'DEVICE-X.Status':'ACTIVE',
'DEVICE-Y.Id':'123EFEF8', 'DEVICE-Y.Type':'DEVICE-Y', 'DEVICE-Y.Status':'NOT FOUND', etc
基本上，我希望通過基于設備型別更易于閱讀的內容來消除“device.X”的歧義
這是我的冗長版本：
s = '{"some.info": "ABC","more.info": "DEF","device.0.Id":"12345678", "device.0.Type":"DEVICE-X", ' \
'"device.0.Status":"ACTIVE", "device.1.Id":"123EFEF8", "device.1.Type":"DEVICE-Y", "device.1.Status":"NOT FOUND", ' \
'"device.2.Id":"ABCD4328", "device.2.Type":"DEVICE-Z", "device.2.Status":"SLEEPING", "other.info":"Hello", ' \
'"additional.info":"Hi Again",}'
d = eval(s)
devs = []
for k, v in d.items():
if '.Type' in k:
devs.append((k.split('.Type')[0], v))
for item in devs:
if item[0] in s:
s = s.replace(item[0], item[1])
s = eval(s)
print(s)
uj5u.com熱心網友回復：
您可以通過將資料加載為 json 來解決此問題，然后對其進行迭代：
import json
s = '{"some.info": "ABC","more.info": "DEF","device.0.Id":"12345678", "device.0.Type":"DEVICE-X", "device.0.Status":"ACTIVE", "device.1.Id":"123EFEF8", "device.1.Type":"DEVICE-Y", "device.1.Status":"NOT FOUND", "device.2.Id":"ABCD4328", "device.2.Type":"DEVICE-Z", "device.2.Status":"SLEEPING", "other.info":"Hello", "additional.info":"Hi Again"}'
# load the string to a dictionary
devices_data = json.loads(s)
device_names = {}
for key, value in devices_data.items():
if key.endswith("Type"):
# if the key looks like a device type, store the value
device_names[key.rpartition(".")[0]] = value
renamed_device_data = {}
for key, value in devices_data.items():
x = key.rpartition(".") # split the key apart
if x[0] in device_names: # check if the first part matches a device name
renamed_device_data[f"{device_names[x[0]]}.{x[2]}"] = value # add the new key to the renamed dictionary with the value
else:
renamed_device_data[key] = value # for non-matches, put them in as is
這當然可以優化，但它至少應該起作用！
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