棋盤病毒問題類似于康威的“生命游戲”。規則是任何兩個有感染鄰居的方格都會被感染。
我曾嘗試用Python實作模擬，但存在邏輯錯誤。我認為正在發生的事情是董事會在一輪內更新，所以中間步驟被遺漏了。例如，與
grid = [
[0, 1, 0, 1],
[1, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0]
]
我得到以下輸出：
Initial State of board:
0 1 0 1
1 0 0 0
0 0 0 0
0 0 0 0
State 2 of board:
1 1 1 1
1 1 1 1
0 0 0 0
0 0 0 0
Infinite loop entered.
第一輪應該只顯示
1 1 1 1
1 1 0 0
0 0 0 0
0 0 0 0
除非我弄錯了。
任何人都可以幫我修復邏輯錯誤嗎？
grid = [
[0, 1, 0, 1],
[1, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0]
]
def write(grid):
"""
Writes the lists of lists of booleans
in grid using 0 for False and 1 for True.
"""
for row in grid:
for item in row:
print(f" {item}", end="")
print()
def neighbors(grid, i, j):
"""
Returns the number of live cells
next to grid[i][j]. Does not include diagonals.
"""
num_neighbours = 0
if i > 0:
if grid[i - 1][j]:
num_neighbours = num_neighbours 1
if i < len(grid) - 1:
if grid[i 1][j]:
num_neighbours = num_neighbours 1
if j > 0:
if grid[i][j - 1]:
num_neighbours = num_neighbours 1
if j < len(grid[i]) - 1:
if grid[i][j 1]:
num_neighbours = num_neighbours 1
print(num_neighbours)
return num_neighbours
def update(grid):
"""
Applies the rule of the chessboard virus to grid
and returns a new grid.
"""
new_board = grid[:]
for i in range(len(grid)):
for j in range(len(grid[i])):
num_neighbours = neighbors(grid, i, j)
if num_neighbours >= 2:
new_board[i][j] = 1
return new_board
def check_all_ones(a):
return not any(c != 1 for r in a for c in r)
def main():
"""
Runs the simulation.
"""
global grid
grid = grid
print("Initial State of board:")
print()
write(grid)
state_num = 1
while True:
last_grid = grid[:] # Clone grid.
grid = update(grid)
state_num = state_num 1
print()
print(f"State {state_num} of board:")
print()
write(grid)
if check_all_ones(grid):
print()
print("Virus has spread to whole board.")
break
if grid == last_grid:
print()
print("Infinite loop entered.")
break
if __name__ == "__main__":
main()
uj5u.com熱心網友回復：
我相信問題在于這new_board = grid[:]不是“深”副本 - 各個行串列是來自 的原始串列物件grid，因此更新步驟設定 在第一次掃描中找到所有新填充的鄰居。
如果您new_board = [r.copy() for r in grid]改為初始化，它似乎可以作業。
正如下面@Ramirez 的評論中所指出的，這同樣適用于主回圈中的克隆。
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