我想寫一行代碼，當你輸入4個數字時，計算機在輸入一組數字后自動按回車，我該怎么做？
uj5u.com熱心網友回復：
使用GNU readline或多或少可移植的解決方案：
#include <readline/readline.h>
#include <stdio.h>
#include <stdlib.h>
static int limit_rl(FILE *f)
{
if (rl_end >= 4)
{
return '\n';
}
return rl_getc(f);
}
int main(void)
{
char *str;
rl_getc_function = limit_rl;
str = readline("> ");
printf("%s\n", str);
free(str);
return 0;
}
uj5u.com熱心網友回復：
這取決于您的作業系統：
例如，在 linux 系統上，system呼叫：
#include <stdio.h>
#include <stdlib.h>
int main(void){
int c;
int passwd[4]={0};
system ("/bin/stty raw"); //use system call to make terminal send all keystrokes directly to stdin
for(unsigned short nb_char = 0; nb_char < 4; nb_char )
{
do
{
c=getchar();
}while((c < 48) || (c > 57));
passwd[nb_char] = c;
}
printf("\npassword is:");
for(unsigned short nb_char = 0; nb_char < 4; nb_char )
{
putchar(passwd[nb_char]);
}
system ("/bin/stty cooked");//use system call to set terminal behaviour to more normal behaviour
return 0;
}
輸出是：
1234
password is:1234
對于窗戶，請參閱getch()：
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
int main(void){
int c;
int passwd[4]={0};
for(unsigned short nb_char = 0; nb_char < 4; nb_char )
{
do
{
c=getch();
}while((c < 48) || (c > 57));
passwd[nb_char] = c;
}
printf("\npassword is:");
for(unsigned short nb_char = 0; nb_char < 4; nb_char )
{
putchar(passwd[nb_char]);
}
return 0;
}
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