我遇到的問題是我希望這個矩陣（mat.a）的第一行成為我陣列中矩陣 1 的第一行，然后第二行成為矩陣 2 的第一行，等等. 然后mat.b的第一行成為我陣列中第一個矩陣的第二行，第二行的mat。b 成為陣列的第二個矩陣中的第二行，依此類推。這種趨勢在 mat.c 中繼續存在。我的矩陣的第四行應該是每列值的平均值。另外，我不允許使用 for 回圈
mat.a <- matrix(c(scores$A1, scores$A2, scores$avgA), ncol = 3,
byrow = FALSE)
mat.b <- matrix(c(scores$B1, scores$B2, scores$avgB), ncol = 3,
byrow = FALSE)
mat.c <- matrix(c(scores$C1, scores$C2, scores$avgC), ncol = 3,
byrow = FALSE)
scores.array<- array(c(mat.a,mat.b, mat.c), dim = c(3,3,21))
> dim(mat.a)
[1] 21 3
> dim(scores)
[1] 21 10
> dim(mat.b)
[1] 21 3
> dim(mat.c)
[1] 21 3
分數 score.updated
uj5u.com熱心網友回復：
嘗試這個：
library(tidyverse)
# add the averages
scores <- scores %>%
rowwise() %>%
mutate(avg1 = mean(c_across(ends_with("1"))),
avg2 = mean(c_across(ends_with("2"))),
avg3 = mean(c_across(starts_with("avg")))) %>%
# relocate the columns
relocate(ini, A1,B1,C1,avg1, A2,B2,C2,avg2, avgA,avgB,avgC, avg3)
# create scores array
scores.array = array(scores %>% pivot_longer(cols = A1:avg3) %>% pull(value), dim=c(4,3,21))
# add dim names
dimnames(scores.array) = list(c("A","B","C","mean"), c("Midterm", "Final", "mean"), scores$ini)
輸出（前兩個）：
> scores.array[,,1:2]
, , ZO
Midterm Final mean
A 28.75775 69.28034 49.01905
B 41.37243 27.43836 34.40540
C 10.28646 89.03502 49.66074
mean 26.80555 61.91791 44.36173
, , UE
Midterm Final mean
A 78.83051 64.05068 71.44060
B 36.88455 81.46400 59.17427
C 43.48927 91.44382 67.46655
mean 53.06811 78.98617 66.02714
輸入資料（假資料）：
set.seed(123)
scores = data.frame(
A1 = runif(21)*100,
A2 = runif(21)*100,
B1 = runif(21)*100,
B2 = runif(21)*100,
C1 = runif(21)*100,
C2 = runif(21)*100
)
scores <- scores %>% rowwise() %>%
mutate(ini = paste0(sample(LETTERS,2), collapse="")) %>%
relocate(ini)
scores$avgA = apply(scores[,c("A1","A2")],1,mean)
scores$avgB = apply(scores[,c("B1","B2")],1,mean)
scores$avgC = apply(scores[,c("C1","C2")],1,mean)
ini A1 A2 B1 B2 C1 C2 avgA avgB avgC
<chr> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
1 ZO 28.8 69.3 41.4 27.4 10.3 89.0 49.0 34.4 49.7
2 UE 78.8 64.1 36.9 81.5 43.5 91.4 71.4 59.2 67.5
3 HS 40.9 99.4 15.2 44.9 98.5 60.9 70.2 30.0 79.7
4 JR 88.3 65.6 13.9 81.0 89.3 41.1 76.9 47.4 65.2
5 JL 94.0 70.9 23.3 81.2 88.6 14.7 82.4 52.3 51.7
6 BJ 4.56 54.4 46.6 79.4 17.5 93.5 29.5 63.0 55.5
7 VL 52.8 59.4 26.6 44.0 13.1 30.1 56.1 35.3 21.6
8 TN 89.2 28.9 85.8 75.4 65.3 6.07 59.1 80.6 35.7
9 QN 55.1 14.7 4.58 62.9 34.4 94.8 34.9 33.8 64.6
10 VC 45.7 96.3 44.2 71.0 65.7 72.1 71.0 57.6 68.9
# ... with 11 more rows
uj5u.com熱心網友回復：
這是解決此問題的自然（我認為）方法：
- 用于
array構造 A、B 和 C 位于第三維的陣列。 - 用于
aperm轉置陣列，使 A、B 和 C 位于第一個維度上。 - 用于
colMeans計算第一個維度上的平均值（“按列”）。 - 用于
abind將均值附加到轉置陣列。
nms <- c("A1", "A2", "avgA", "B1", "B2", "avgB", "C1", "C2", "avgC")
z <- array(unlist(scores[nms]), dim = c(21L, 3L, 3L))
zz <- aperm(zz, 3:1)
zzz <- abind::abind(zz, colMeans(zz, dims = 1L), along = 1L)
zzz[, , 1:2]
, , 1
[,1] [,2] [,3]
[1,] 28.75775 69.28034 49.01905
[2,] 41.37243 27.43836 34.40540
[3,] 10.28646 89.03502 49.66074
[4,] 26.80555 61.91791 44.36173
, , 2
[,1] [,2] [,3]
[1,] 78.83051 64.05068 71.44060
[2,] 36.88455 81.46400 59.17427
[3,] 43.48927 91.44382 67.46655
[4,] 53.06811 78.98617 66.02714
我用過scores@langtang 定義的（非常有幫助！）。
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