我有一個像這樣的花車串列
numbers = [0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9]
我想要一個可以為給定總和(=1)和給定數量的元素生成所有可能組合的python代碼,例如:
numbers = [0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9]
sum = 1
number of elements = 3
輸出:
[(0.1, 0.1, 0.8), (0.1, 0.2, 0.7), (0.1, 0.3, 0.6), (0.1, 0.4, 0.5), (0.1, 0.5, 0.4), (0.1, 0.6, 0.3), (0.1, 0.7, 0.2), (0.1, 0.8, 0.1), (0.2, 0.1, 0.7), (0.2, 0.2, 0.6), (0.2, 0.3, 0.5), (0.2, 0.4, 0.4), (0.2, 0.5, 0.3), (0.2, 0.6, 0.2), (0.2, 0.7, 0.1), (0.3, 0.1, 0.6), (0.3, 0.2, 0.5), (0.3, 0.3, 0.4), (0.3, 0.4, 0.3), (0.3, 0.5, 0.2), (0.3, 0.6, 0.1), (0.4, 0.1, 0.5), (0.4, 0.2, 0.4), (0.4, 0.3, 0.3), (0.4, 0.4, 0.2), (0.4, 0.5, 0.1), (0.5, 0.1, 0.4), (0.5, 0.2, 0.3), (0.5, 0.3, 0.2), (0.5, 0.4, 0.1), (0.6, 0.1, 0.3), (0.6, 0.2, 0.2), (0.6, 0.3, 0.1), (0.7, 0.1, 0.2), (0.7, 0.2, 0.1), (0.8, 0.1, 0.1)]
uj5u.com熱心網友回復:
一個非常簡單的方法是使用itertools.combinations生成所有可能的組合,并選擇那些產生所需總和的組合。
>>> import itertools
>>> numbers = [0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9]
>>> target_sum = 1
>>> number = 3
>>> [c for c in itertools.combinations(numbers, number) if sum(c) == target_sum]
[(0.1, 0.2, 0.7), (0.1, 0.3, 0.6), (0.1, 0.4, 0.5), (0.2, 0.3, 0.5)]
如果您希望所有可能的不同排序作為不同的解決方案,請itertools.permutations改用:
>>> [c for c in itertools.permutations(numbers, number) if sum(c) == target_sum]
[(0.1, 0.2, 0.7), (0.1, 0.3, 0.6), (0.1, 0.4, 0.5), (0.1, 0.5, 0.4), (0.1, 0.6, 0.3), (0.1, 0.7, 0.2), (0.2, 0.1, 0.7), (0.2, 0.3, 0.5), (0.2, 0.5, 0.3), (0.3, 0.1, 0.6), (0.3, 0.2, 0.5), (0.3, 0.5, 0.2), (0.4, 0.1, 0.5), (0.4, 0.5, 0.1), (0.5, 0.1, 0.4), (0.5, 0.2, 0.3), (0.5, 0.3, 0.2), (0.5, 0.4, 0.1), (0.6, 0.1, 0.3), (0.7, 0.1, 0.2)]
如果您希望能夠多次使用每個元素,請使用itertools.combinations_with_replacement:
>>> [c for c in itertools.combinations_with_replacement(numbers, number) if sum(c) == target_sum]
[(0.1, 0.1, 0.8), (0.1, 0.2, 0.7), (0.1, 0.3, 0.6), (0.1, 0.4, 0.5), (0.2, 0.2, 0.6), (0.2, 0.3, 0.5), (0.2, 0.4, 0.4), (0.3, 0.3, 0.4)]
如果您想多次使用元素并獲得所有可能的排序,請使用itertools.product:
>>> [c for c in itertools.product(numbers, repeat=number) if sum(c) == target_sum]
[(0.1, 0.1, 0.8), (0.1, 0.2, 0.7), (0.1, 0.3, 0.6), (0.1, 0.4, 0.5), (0.1, 0.5, 0.4), (0.1, 0.6, 0.3), (0.1, 0.7, 0.2), (0.1, 0.8, 0.1), (0.2, 0.1, 0.7), (0.2, 0.2, 0.6), (0.2, 0.3, 0.5), (0.2, 0.4, 0.4), (0.2, 0.5, 0.3), (0.2, 0.6, 0.2), (0.3, 0.1, 0.6), (0.3, 0.2, 0.5), (0.3, 0.3, 0.4), (0.3, 0.4, 0.3), (0.3, 0.5, 0.2), (0.4, 0.1, 0.5), (0.4, 0.2, 0.4), (0.4, 0.3, 0.3), (0.4, 0.4, 0.2), (0.4, 0.5, 0.1), (0.5, 0.1, 0.4), (0.5, 0.2, 0.3), (0.5, 0.3, 0.2), (0.5, 0.4, 0.1), (0.6, 0.1, 0.3), (0.6, 0.2, 0.2), (0.7, 0.1, 0.2), (0.8, 0.1, 0.1)]
轉載請註明出處,本文鏈接:https://www.uj5u.com/qukuanlian/444849.html
標籤:Python 数组 python-3.x
上一篇:Rust特殊陣列
