我正在嘗試構建一個收銀機（FreeCodeCamp 中的一個演算法專案），并且我創建了一個函式（giveChange()，一個遞回函式）以在另一個單獨的函式（checkCashRegister）中呼叫。
但是，該函式沒有被呼叫。我希望函式 checkCashRegister 在我的情況下回傳 0。
我檢查了是否是在for回圈中將“return”放置在錯誤位置的問題或范圍問題。似乎也沒有。
function giveChange(diff, cid) {
for(let i = cid.length - 1; i > 0; i--) {
if(cid[i-1][0] <= diff && diff <= cid[i][0]) {
diff = diff - Math.min(cid[i-1][1], cid[i-1][0]*Math.ceil(((diff-cid[i-1][0])/cid[i-1][0])))
if(diff !== 0) {
giveChange(diff, cid)
} else {
return diff
}
}
}
return diff
}
function checkCashRegister(price, cash, cid) {
let diff = cash - price
cid[0][0] = 0.01
cid[1][0] = 0.05
cid[2][0] = 0.1
cid[3][0] = 0.25
cid[4][0] = 1
cid[5][0] = 5
cid[6][0] = 10
cid[7][0] = 20
cid[8][0] = 100
giveChange(diff, cid)
return diff
}
checkCashRegister(3.26, 100, [["PENNY", 1.01], ["NICKEL", 2.05], ["DIME", 3.1], ["QUARTER", 4.25], ["ONE", 90], ["FIVE", 55], ["TEN", 20], ["TWENTY", 60], ["ONE HUNDRED", 100]])
uj5u.com熱心網友回復：
您return在呼叫之前缺少關鍵字givechange(diff, cid)，
注意：我已經更新了條件并使用了三元來不重復return關鍵字
function giveChange(diff, cid) {
for (let i = cid.length - 1; i > 0; i--) {
if (cid[i - 1][0] <= diff && diff <= cid[i][0]) {
diff = diff - Math.min(cid[i - 1][1], cid[i - 1][0] * Math.ceil(((diff - cid[i - 1][0]) / cid[i - 1][0])))
return diff !== 0 ? giveChange(diff, cid) : diff
}
}
console.log(diff)
return diff
}
function checkCashRegister(price, cash, cid) {
let diff = cash - price
cid[0][0] = 0.01
cid[1][0] = 0.05
cid[2][0] = 0.1
cid[3][0] = 0.25
cid[4][0] = 1
cid[5][0] = 5
cid[6][0] = 10
cid[7][0] = 20
cid[8][0] = 100
return giveChange(diff, cid)
}
checkCashRegister(3.26, 100, [
["PENNY", 1.01],
["NICKEL", 2.05],
["DIME", 3.1],
["QUARTER", 4.25],
["ONE", 90],
["FIVE", 55],
["TEN", 20],
["TWENTY", 60],
["ONE HUNDRED", 100]
])轉載請註明出處，本文鏈接：https://www.uj5u.com/qukuanlian/448934.html
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