我想得到一個帶有過濾值的陣列。我的陣列就像，
let arr=[{name:'trt,tet', id:5},{name:td, id:25},{name:fxg, id:1},{name:fs, id:4},{name:ste, id:41}]
&
let arr1 =[{data:fxg, addr:po 87987},{data:tert, addr:po8798fvd7},{data:trt, addr:po 887},{data:trhd, addr:po 8798787}]
我想要的結果陣列是，
let rslt =[data:tert, addr:po8798fvd7},{data:trhd, addr:po 8798787}]
那是在 arr 中的物件“名稱”，它也在 arr1 中，名稱為“資料”，我不需要那個陣列。發現其中一些包含多個名稱。我想過濾它。
uj5u.com熱心網友回復：
試試這個
let arr=[{name:'trt,tet', id:5},{name:'td', id:25},{name:'fxg', id:1},{name:'fs', id:4},{name:'ste', id:41}]
let arr1 =[{data:'fxg', addr:'po 87987'},{data:'tert', addr:'po8798fvd7'},{data:'trt', addr:'po 887'},{data:'trhd', addr:'po 8798787'}]
const names = arr.flatMap(a => a.name.split(','))
const res = arr1.filter(a => !names.includes(a.data))
console.log(res)uj5u.com熱心網友回復：
這使用Set為查找優化的a，O(1)因此演算法的運行時間O(n)與使用includes()將導致運行時間為O(n2).
let arr = [
{ name: "trt", id: 5 },
{ name: "td", id: 25 },
{ name: "fxg", id: 1 },
{ name: "fs", id: 4 },
{ name: "ste", id: 41 },
];
let arr1 = [
{ data: "fxg", addr: "po87987" },
{ data: "tert", addr: "po8798fvd7" },
{ data: "trt", addr: "po887" },
{ data: "trhd", addr: "po8798787" },
];
// use array for quick lookups in O(1)
const set = new Set(arr.map(item => item.name));
// filter arr1 adding only items to result that are not in Set
const result = arr1.filter(item => !set.has(item.data))
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }轉載請註明出處，本文鏈接：https://www.uj5u.com/qukuanlian/466516.html
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