我得到多個路徑陣列包含以下關鍵字“標題”：
jq -c 'paths | select(.[-1] == "headline")' nytimeseuro.json
["data","legacyCollection","collectionsPage","stream","edges",0,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",1,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",2,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",3,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",4,"node","headline"]
["data","legacyCollection","headline"]
我可以根據陣列索引選擇它們嗎？像 Output[0:2] 只選擇
["data","legacyCollection","collectionsPage","stream","edges",0,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",1,"node","headline"]
["data","legacyCollection","collectionsPage","stream","edges",2,"node","headline"]
或 Output[-1] 只選擇
["data","legacyCollection","headline"]
我嘗試了下面的命令，但這似乎不是我想要的，它只是分割了我得到的每條路徑，而不是選擇回傳的所有路徑的子集：
jq -c 'paths | select(.[-1] == "headline")[:3]' nytimeseuro.json
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","collectionsPage"]
["data","legacyCollection","headline"]
uj5u.com熱心網友回復：
paths生成一個流，而您顯然需要一個陣列，您可以從中輕松提取感興趣的專案。例如：
[paths | select(.[-1] == "headline")][0:2]
面向流的替代方案也可用，例如 limit(2; paths ....)
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