我有這兩個集合和一個用戶集合，我想為一個用戶制作一個提供者串列
我試過這段代碼但沒有給我結果:(
Future<List<ServineraProvider>> getfavoritesForUser() async{
List<ServineraProvider> providers = [];
await providerSkillsCollection.where('providerID', isEqualTo: this.uid).get()
.then((onValue){
for(int i=0; i<onValue.docs.length; i ){
var doc = onValue.docs[i].data() as Map<String,dynamic>;
print(doc['skillID']);
skillsCollection.doc(doc['skillID']).get()
.then((doc){
var data = doc.data() as Map<String,dynamic>;
providers.add(ServineraProvider(
providerID: data['providerID'],
providerName: data['providerName'],
providerEmail: data['providerEmail'],
providerPhoneNumber: data['providerPhoneNumber'],
providerPicture: data['providerPicture'],
providerState: data['providerState'],
providerStatus: data['providerStatus']
)
);
});
}
});
return providers;
}
我知道有錯誤但無法解決
uj5u.com熱心網友回復：
您正在與 結合then，await這幾乎不是一個好主意。在這種情況下，它會在查詢完成后回傳串列，但在providers加載任何提供程式本身之前。providerSkillsCollection
要解決問題，只需await：
Future<List<ServineraProvider>> getfavoritesForUser() async{
List<ServineraProvider> providers = [];
var onValue = await providerSkillsCollection.where('providerID', isEqualTo: this.uid).get()
for(int i=0; i<onValue.docs.length; i ){
var doc = onValue.docs[i].data() as Map<String,dynamic>;
print(doc['skillID']);
var doc = await skillsCollection.doc(doc['skillID']).get()
var data = doc.data() as Map<String,dynamic>;
providers.add(ServineraProvider(
providerID: data['providerID'],
providerName: data['providerName'],
providerEmail: data['providerEmail'],
providerPhoneNumber: data['providerPhoneNumber'],
providerPicture: data['providerPicture'],
providerState: data['providerState'],
providerStatus: data['providerStatus']
));
}
return providers;
}
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