如何在擁有我想要的孩子的同一個父母中找到一個標簽？

抓取一個在同一頁面上有多個產品的網站，有些我不想知道價格。所以我想先看產品類別，然后再列出價格。

網站代碼如下所示：

<section class="products_results">
   <span something I don't want>...</span>
   <section >
      <span>Clothes</span>
   <div something I don't want>...</div>
   <section class="search_result_price">
      <section>
         <span something I don't want>...</span>
         <span >149.99</span>
      </section>
</section>

我已經知道如何使用自己的代碼進入類別部分，但我完全被困在另一部分。

for products in soup.find_all(class_='category'):
   category = (products.text)
   if category == 'Clothes':
      price = (theoretical piece of code)

如何訪問此父標簽中的特定價格<section>標簽？

uj5u.com熱心網友回復：

從正則運算式使用

Import re
Pat = '''
price">(/d*./d*)</span>
'''
price = re.find_all(your text,pat)

uj5u.com熱心網友回復：

使用 CSS 選擇器，它按預期作業。

html='''
<section >
   <span something I don't want>...</span>
   <section >
      <span>Clothes</span>
   <div something I don't want>...</div>
   <section >
      <section>
         <span something I don't want>...</span>
         <span >149.99</span>
      </section>
</section>
'''
from bs4 import BeautifulSoup
soup = BeautifulSoup(html,'lxml')
for p in soup.select('.category section.search_result_price span.price'):
    print(p.text)

輸出：

149.99

uj5u.com熱心網友回復：

您已接近目標，但請注意，這products.text將為您提供整個部分的文本，更好地用于products.span.text僅獲取類別文本。

要獲取價格資訊，只需找到 span并檢查它是否可用以避免錯誤：

price = products.find(class_='price').text if products.find('span', class_='price') else None

例子

from bs4 import BeautifulSoup

html='''
<section >
   <span something I don't want>...</span>
   <section >
      <span>Clothes</span>
   <div something I don't want>...</div>
   <section >
      <section>
         <span something I don't want>...</span>
         <span >149.99</span>
      </section>
</section>'''

soup = BeautifulSoup(html, 'html.parser')

for products in soup.find_all('section', class_='category'):
    category = products.span.text
    if category == 'Clothes':
        price = products.find(class_='price').text if products.find('span', class_='price') else None
        print(price)

輸出

149.99

作為替代方法，更精簡的方法是創建易于處理的結構化輸出并處理允許的類別串列：

from bs4 import BeautifulSoup

    html='''
    <section >
       <span something I don't want>...</span>
       <section >
          <span>Clothes</span>
       <div something I don't want>...</div>
       <section >
          <section>
             <span something I don't want>...</span>
             <span >149.99</span>
          </section>
       <span something I don't want>...</span>
       <section >
          <span>Shoes</span>
       <div something I don't want>...</div>
       <section >
          <section>
             <span something I don't want>...</span>
             <span >90.99</span>
          </section>
    </section>'''
    
    soup = BeautifulSoup(html, 'html.parser')
    
    data = []
    
    c_list = ['Clothes','Shoes']
    
    for products in soup.select(f"section.category:-soup-contains({','.join(c_list)})"):
        data.append({
            'category' : products.span.text,
            'price' : products.find(class_='price').text if products.find('span', class_='price') else None
        })
    
    data

輸出

[{'category': 'Clothes', 'price': '149.99'},
 {'category': 'Shoes', 'price': '90.99'}]

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