如何從nodejs中的物件獲取值？
let person = {temperature:[35,36],humidity:[85,90,89};
let y = req.query.id; (which is `temperature`)
console.log(person.y);
uj5u.com熱心網友回復：
為了從 nodejs 物件中獲取值，您可以通過以下方式進行操作
直接獲取person.temparature或person[myvar]
或通過迭代：
for (const [key, value] of Object.entries(person)) {
console.log(`${key}: ${value}`); // key = 'temperature', value = [35,36] for the first entry (temperature)
}
來源：https ://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/entries
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/Property_Accessors
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標籤：节点.js数据库目的
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