我正在嘗試將 DataGridView 資料保存到 Access 資料庫(資料庫已連接到 Visual Studio)。
這是我的代碼:
Private Sub Button4_Click(sender As Object, e As EventArgs) Handles Button4.Click
Try
Dim cn As OleDbConnection
cn = New OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source= |DataDirectory|\GEFORSERVI V2.1.accdb;")
cn.Open()
Dim cmd As New OleDbCommand
cmd.Connection = cn
cmd.CommandType = Data.CommandType.Text
Dim Strcommandtext As String = "inserto into Factura(Designacao,PrecoUnitario,Qtd,Total,Nome,Entidade,NIF,Telefone,Morada,CodigoProduto,DataEmissao) VALUES(@Servico_Produto,@Valor,@Qtd,@Total,@Nome,@Entidade,@NIF,@Telemovel,@Bairro,@Data_de_Emissao)"
Dim values As String = ""
For i As Integer = 0 To Factura2DataGridView.Rows.Count - 1
values = Strcommandtext & Factura2DataGridView.Rows(i).Cells(11).Value & ")"
cmd.CommandText = values
cmd.ExecuteNonQuery()
Next i
cmd = Nothing
cn.Close()
MsgBox("Your Record Inserted Successfully ")
Catch myException As Exception
MsgBox("No Record Inserted" myException.ToString())
Finally
'MsgBox("Closing Connection")
End Try
End Sub
uj5u.com熱心網友回復:
Connections 和Commands 需要處理,以便它們可以釋放非托管資源。Using...End Using塊是處理此問題的最佳方法,因為即使出現錯誤也會執行此操作。在這段代碼中,我的連接和命令都包含在Using塊中。注意第一Using行末尾的逗號。
將CommandText和Connection直接傳遞給命令的建構式。我注意到您錯過了欄位串列中的一個引數。我也注意到你輸入了“inserto”。我相信它必須是“插入”。不需要設定,CommandType因為CommandType.Text是默認值。
在 OleDb 中,引數出現在 sql 字串中的順序必須與它們添加到引數集合中的順序相匹配。
在回圈外構建引數集合。只有引數的值在回圈中發生變化。
在回圈外打開連接一次。
Private Sub Button4_Click(sender As Object, e As EventArgs) Handles Button4.Click
Try
Using cn As New OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source= |DataDirectory|\GEFORSERVI V2.1.accdb;"),
cmd As New OleDbCommand("Insert into Factura(Designacao,PrecoUnitario,Qtd,Total,Nome,Entidade,NIF,Telefone,Morada,CodigoProduto,DataEmissao)
VALUES(@Servico_Produto,@Valor,@Qtd,@Total,@Nome,@Entidade,@NIF,@Telemovel,@Bairro,@CodigoProduto,@Data_de_Emissao)", cn)
With cmd.Parameters
.Add("@Servico_Produto", OleDbType.Integer)
.Add("@Valor", OleDbType.VarWChar)
.Add("@Qtd", OleDbType.Integer)
.Add("@Total", OleDbType.Decimal)
.Add("@Nome", OleDbType.VarWChar)
.Add("@Entidade", OleDbType.VarWChar)
.Add("@NIF", OleDbType.VarWChar)
.Add("@Telemovel", OleDbType.VarWChar)
.Add("@Bairro", OleDbType.VarWChar)
.Add("@CodigoProduto", OleDbType.Integer)
.Add("@Data_de_Emissao", OleDbType.Date)
End With
cn.Open()
For i As Integer = 0 To Factura2DataGridView.Rows.Count - 1
cmd.Parameters("@Servico_Produto").Value = Factura2DataGridView.Rows(i).Cells(0).Value
cmd.Parameters("@Valor").Value = Factura2DataGridView.Rows(i).Cells(1).Value
cmd.Parameters("@Qtd").Value = Factura2DataGridView.Rows(i).Cells(2).Value
cmd.Parameters("@Total").Value = Factura2DataGridView.Rows(i).Cells(3).Value
cmd.Parameters("@Nome").Value = Factura2DataGridView.Rows(i).Cells(4).Value
cmd.Parameters("@Entidade").Value = Factura2DataGridView.Rows(i).Cells(5).Value
cmd.Parameters("@NIF").Value = Factura2DataGridView.Rows(i).Cells(6).Value
cmd.Parameters("@Telemovel").Value = Factura2DataGridView.Rows(i).Cells(7).Value
cmd.Parameters("@Bairro").Value = Factura2DataGridView.Rows(i).Cells(8).Value
cmd.Parameters("@CodigoProduto").Value = Factura2DataGridView.Rows(i).Cells(9).Value
cmd.Parameters("@Data_de_Emissao").Value = Factura2DataGridView.Rows(i).Cells(10).Value
cmd.ExecuteNonQuery()
Next
End Using
MsgBox("Your Record Inserted Successfully ")
Catch myException As Exception
MsgBox("No Record Inserted" myException.Message)
End Try
End Sub
有更簡單的方法可以做到這一點。如果你有一個DataTable系結,DataGridView你可以使用一個DataAdpater.Update方法。
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