如何逐行迭代Python中串列的元素？

我有以下代碼來搜索文本檔案并提取某些元素之間的文本部分： start="a owl:Class" end=' .\n' 并將這些文本部分附加為串列的元素。

contents = []
with open(r'C:/Users/Jupyter Notebooks/small.ttl', 'r', encoding="UTF-8") as f:
   recording = False
   content = ''
   for line in f:
      if start in line:
         recording = True
      if recording and end in line:
         recording = False
         contents.append(content)
      if recording:
         content  = line
      else:
         content = ''
for i in contents
    print (i)

串列內容包含兩個由文本字串組成的元素。每行文本都以一個新行開始 第一個元素：

http://purl.bioontology.org/ontology/SNOMEDCT/1075251000119104貓頭鷹：類；skos:prefLabel """獲得性左跖骨內收肌"""@en ; skos:notation """1075251000119104"""^^xsd:string ; skos:altLabel """獲得性左跖骨內收肌（障礙）"""@en ; http://purl.bioontology.org/ontology/SNOMEDCT/has_finding_site http://purl.bioontology.org/ontology/SNOMEDCT/726438004； http://purl.bioontology.org/ontology/SNOMEDCT/has_associated_morphology http://purl.bioontology.org/ontology/SNOMEDCT/767172008； http://purl.bioontology.org/ontology/SNOMEDCT/occurs_in http://purl.bioontology.org/ontology/SNOMEDCT/767023003；rdfs： ; rdfs:subClassOf http://purl.bioontology.org/ontology/SNOMEDCT/774124003；

第二個要素：

http://purl.bioontology.org/ontology/SNOMEDCT/10308009貓頭鷹：類；skos:prefLabel """Argon-42"""@en ; skos:notation """10308009"""^^xsd:string ; skos:altLabel """42-Ar"""@en , """Argon-42 (substance)"""@en ; rdfs:subClassOf http://purl.bioontology.org/ontology/SNOMEDCT/35016001； http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000508004~ACCEPTABILITYID~900000000000548007"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/TYPE_ID """9000000000000013009"""^^xsd:string ; http://purl.bioontology。 org/ontology/SNOMEDCT/CASE_SIGNIFICANCE_ID """ 900000000000017005 """"^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000509007~可接受ID~900000000000548007"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/INACTIVATION_INDICATOR """723277005""""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000490003~VALUEID~723277005"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000509007~ACCEPTABILITYID~900000000000548007"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/TYPE_ID """9000000000000013009"""^^xsd:string ; http://purl.bioontology。 org/ontology/SNOMEDCT/CASE_SIGNIFICANCE_ID """ 900000000000448009 """"^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000508004~可接受ID~900000000000548007"""^^xsd:string ;

我想逐行檢查每個串列元素并檢查該行是否包含某個字串。例如：

if "a:owl Class" in line:
                  print line

我的問題是我無法遍歷串列元素的行。

uj5u.com熱心網友回復：

所以我做了這個。

首先，我將您的 2 個元素轉換為字串并將它們放入串列中。

string1 = 'http://purl.bioontology.org/ontology/SNOMEDCT/1075251000119104 a owl:Class ; skos:prefLabel """Acquired left metatarsus adductus"""@en ; skos:notation """1075251000119104"""^^xsd:string ; skos:altLabel """Acquired left metatarsus adductus (disorder)"""@en ; http://purl.bioontology.org/ontology/SNOMEDCT/has_finding_site http://purl.bioontology.org/ontology/SNOMEDCT/726438004 ; http://purl.bioontology.org/ontology/SNOMEDCT/has_associated_morphology http://purl.bioontology.org/ontology/SNOMEDCT/767172008 ; http://purl.bioontology.org/ontology/SNOMEDCT/occurs_in http://purl.bioontology.org/ontology/SNOMEDCT/767023003 ; rdfs:subClassOf http://purl.bioontology.org/ontology/SNOMEDCT/99701000119102 ; rdfs:subClassOf http://purl.bioontology.org/ontology/SNOMEDCT/774124003 ;'
string2 = 'http://purl.bioontology.org/ontology/SNOMEDCT/10308009 a owl:Class ; skos:prefLabel """Argon-42"""@en ; skos:notation """10308009"""^^xsd:string ; skos:altLabel """42-Ar"""@en , """Argon-42 (substance)"""@en ; rdfs:subClassOf http://purl.bioontology.org/ontology/SNOMEDCT/35016001 ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000508004~ACCEPTABILITYID~900000000000548007"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/TYPE_ID """900000000000013009"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/CASE_SIGNIFICANCE_ID """900000000000017005"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000509007~ACCEPTABILITYID~900000000000548007"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/INACTIVATION_INDICATOR """723277005"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000490003~VALUEID~723277005"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000509007~ACCEPTABILITYID~900000000000548007"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/TYPE_ID """900000000000013009"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/CASE_SIGNIFICANCE_ID """900000000000448009"""^^xsd:string ; http://purl.bioontology.org/ontology/SNOMEDCT/SUBSET_MEMBER """900000000000508004~ACCEPTABILITYID~900000000000548007"""^^xsd:string ;'
contents = [string1,string2]

從這部分開始，您應該能夠重現我的代碼。

首先，我遍歷串列中的每個專案。

然后我使用 將每一行拆分為一個串列;作為分隔符。

然后我在串列中的每個專案上迭代每個串列以查找您的字串。

for content in contents:
    for line in content.split(';'):
        if 'a owl:Class' in line:
            print(i)

這是我的輸出，

http://purl.bioontology.org/ontology/SNOMEDCT/1075251000119104 a owl:Class 
http://purl.bioontology.org/ontology/SNOMEDCT/10308009 a owl:Class 

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