#include <stdio.h>
int main() {
int x,y,add,subtraction,multiplication,division;
printf("Write x:");
scanf("%d",&x);
printf("Write y:");
scanf("%d",&y);
add = x y;
printf("Add=%d\n",add);
subtraction = x-y;
printf("subtraction = %d\n",subtraction);
multiplication = x*y;
printf("multiplication = %d\n",multiplication);
division = x/y;
if (y == 0)
printf("Operation not permitted");
else
printf("division = %d\n",division);
return 0;
}
因此，當我列印 y=0 時什么也沒有發生 沒有“不允許操作”或除法答案 我該怎么辦？
uj5u.com熱心網友回復：
只需放置此陳述句
division = x/y;
在 if 陳述句中，如
if (y == 0)
{
printf("Operation not permitted");
}
else
{
division = x/y;
printf("division = %d\n",division);
}
return 0;
uj5u.com熱心網友回復：
使分裂發生在else. 像這樣：
#include <stdio.h>
int main()
{
int x,y,sum,roz,iloczyn,iloraz;
printf("Wprowadz x:");
scanf("%d",&x);
printf("Wprowadz y:");
scanf("%d",&y);
sum = x y;
printf("Suma=%d\n",sum);
roz = x-y;
printf("roznica = %d\n",roz);
iloczyn = x*y;
printf("iloczyn = %d\n",iloczyn);
if (y == 0)
{
printf("Operation not permitted");
exit(0);
}
else
{
iloraz = x/y;
printf("iloraz = %d\n",iloraz);
return 0;
}
}
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