如何將Laravel陣列轉換為ruby??哈希訪問

我有一個陣列來存盤一些這樣的資料，這是我正在使用的確切輸入

{
    "accepted" => {
        "number_of_order" => {
            "condition" => "between_number", "value" => "0&5"
        }
    }, "removed" => {
        
    }
}

現在我正在嘗試將此陣列轉換為這樣的 ruby?? 哈希訪問，這是我的預期輸出，這不是我現在得到的

--- !ruby/hash:ActiveSupport::HashWithIndifferentAccess
accepted: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
  number_of_order: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
    condition: between_number
    value: 0&5
removed: !ruby/hash:ActiveSupport::HashWithIndifferentAccess {}

但我無法在 ruby?? 哈希訪問中轉換陣列。我還嘗試將 YAML 轉儲Yaml::dump($array);轉換為 YAML，然后使用 ruby?? 哈希訪問，但沒有任何效果。

基本上，我試圖扭轉這個問題

如何從 ruby?? 哈希訪問 Laravel 8 獲取資料？

您可以參考上面的鏈接，我將此 ruby?? 哈希轉換為 laravel 陣列，但現在我也想將此陣列轉換為 ruby?? 哈希。

我當前用于將陣列轉換為 ruby?? 哈希的代碼

$jsonEncoded = '{"accepted":{"number_of_order":{"consition":"between_number","value":"0&5"}}}';

$array = json_decode($jsonEncoded, true);

dump(Yaml::dump($array));

我當前用于將 ruby?? 哈希轉換為陣列的代碼

$filter_data = str_replace("!ruby/hash:ActiveSupport::HashWithIndifferentAccess", "", $filter_data);
$yamlContents = Yaml::parse($filter_data);

uj5u.com熱心網友回復：

要在 ruby?? 中將哈希轉換為 yaml，我們可以使用yaml庫

require 'yaml'

data = {
    "accepted" => {
        "number_of_order" => {
            "condition" => "between_number", "value" => "0&5"
        }
    }, "removed" => {
        
    }
}

puts data.to_yaml

要將關聯陣列轉換為 php 中的 yaml，我們可以使用 Symfony Yaml

use Symfony\Component\Yaml\Yaml;

$jsonEncoded = '{"accepted":{"number_of_order":{"consition":"between_number","value":"0&5"}}}';

$array = json_decode($jsonEncoded, true);

print Yaml::dump($array);

要在 ruby?? 中加載 php 輸出 yamlyaml可以使用相同的庫

require 'yaml'
yaml_str = ... # output generate from Symfony Yaml::dump
yaml_hash = YAML.load(yaml_str)

要在 php 中加載 ruby?? 輸出 yaml，我們可以使用相同的 Symfony Yaml

$yaml_str = ...; # output generate from ruby rhash.to_yaml
$yaml_associated_array = Yaml.parse(yaml_str);

將 ruby?? 哈希加載到 php

$data = "
--- !ruby/hash:ActiveSupport::HashWithIndifferentAccess
accepted: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
  number_of_order: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
    condition: between_number
    value: 0&5
removed: !ruby/hash:ActiveSupport::HashWithIndifferentAccess {}
";

print $data;

$data = str_replace("---", "", preg_replace("/!ruby.*Access/", "", $data));
print $data;

$result = Yaml::parse($data);
var_dump($result);

同樣可以在 ruby?? 中實作

data = %Q(
--- !ruby/hash:ActiveSupport::HashWithIndifferentAccess
accepted: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
  number_of_order: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
    condition: between_number
    value: 0&5
removed: !ruby/hash:ActiveSupport::HashWithIndifferentAccess {}
)

result = str.gsub(/!ruby.*Access/, '').gsub("--- ", "")

puts result

puts YAML.load(result)

注意：我們也可以使用其他庫

uj5u.com熱心網友回復：

我剛剛找到了我的問題的答案，我正在與大家分享。

Laravel 代碼：

$jsonEncoded = '{"accepted":{"first_order_number":{"consition":"between_date","value":"2021-11-28 00:00:00&2021-11-22 00:00:00"}},"removed":{}}';
    
$process = new Process(['ruby', 'convert_hashActiveSupport.rb'],null,null, $jsonEncoded);

$process->run();
    
// executes after the command finishes
if (!$process->isSuccessful()) {
   throw new ProcessFailedException($process);
}
    
$data = $process->getOutput();

紅寶石代碼：

require 'yaml'
require 'json'
require "active_support/core_ext/hash/indifferent_access"

yaml_str = "#{ ARGF.read }"

parsed_output = JSON.parse(yaml_str)
yaml_output   = parsed_output.with_indifferent_access.to_yaml
puts yaml_output

laravel 中需要的包：

composer require symfony/process

ruby 中需要的包：

gem install activesupport
gem install 'yaml'

在這里，我得到了預期的輸出：

--- !ruby/hash:ActiveSupport::HashWithIndifferentAccess
accepted: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
  first_order_date: !ruby/hash:ActiveSupport::HashWithIndifferentAccess
    consition: between_date
    value: 2021-11-28 00:00:00&2021-11-22 00:00:00
removed: !ruby/hash:ActiveSupport::HashWithIndifferentAccess {}

標籤：红宝石 拉拉维尔

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