如何在單獨的陣列中計算陣列中的每個物件？-有解無憂

我有這個陣列

bidsList = [
    {
      supplierName:'A',
      awardedCapacity:5,
    },
    {
      supplierName:'B',
      awardedCapacity:10,
    },
    {
      supplierName:'A',
      awardedCapacity:5,
    },
    {
      supplierName:'A',
      awardedCapacity:3,
    },
    {
      supplierName:'B',
      awardedCapacity:5,
    },
    {
      supplierName:'C',
      awardedCapacity:2,
    },

我需要有單獨的陣列，當我通過這個陣列進行迭代時，我將計算供應商名稱相同的所有授予的容量的總數

例如，我應該有陣列，在那里我將有這個輸出

 let newArr = [
    {
      supplierName: 'A',
      totalAwarded: 13,
    },
    {
      supplierName:'B',
      totalAwarded: 15,
    },
    {
      supplierName:'C',
      totalAwarded: 2,
    }
  ]

因為在之前的陣列中，我有three 一個供應商名稱所在的物件，A當我將他們獲得的容量相加時，我在另一個物件中得到了 13 的供應商名稱

uj5u.com熱心網友回復：

您可以嘗試使用Array.prototype.reduce()如下方式：

let bidsList = [
    {
      supplierName:'A',
      awardedCapacity:5,
    },
    {
      supplierName:'B',
      awardedCapacity:10,
    },
    {
      supplierName:'A',
      awardedCapacity:5,
    },
    {
      supplierName:'A',
      awardedCapacity:3,
    },
    {
      supplierName:'B',
      awardedCapacity:5,
    },
    {
      supplierName:'C',
      awardedCapacity:2,
    }
  ];
  
let newArr = [];
bidsList.reduce(function(acc, val) {
  if (!acc[val.supplierName]) {
    acc[val.supplierName] = { supplierName: val.supplierName, awardedCapacity: 0 };
    newArr.push(acc[val.supplierName])
  }
  acc[val.supplierName].awardedCapacity  = val.awardedCapacity;
  return acc;
}, {});

console.log(newArr);

uj5u.com熱心網友回復：

Array.reduce

    const newArr = bidsList.reduce((a, o) =>  {  
      const index  = a.findIndex(x => x.supplierName === o.supplierName);
      const s = a[index > -1 ? index: a.push({supplierName:o.supplierName, awardedCapacity:0}) - 1];
      s.awardedCapacity  = o.awardedCapacity;
      return a;
    }, [])

uj5u.com熱心網友回復：

使用Array.reduce方法

var bidsList = [
    {
      supplierName:'A',
      awardedCapacity:5,
    },
    {
      supplierName:'B',
      awardedCapacity:10,
    },
    {
      supplierName:'A',
      awardedCapacity:5,
    },
    {
      supplierName:'A',
      awardedCapacity:3,
    },
    {
      supplierName:'B',
      awardedCapacity:5,
    },
    {
      supplierName:'C',
      awardedCapacity:2,
    }];

var result = bidsList.reduce((a, c) => {

  let supplier = a.find(e => e.supplierName == c.supplierName);
  if (supplier)
    supplier.totalAwarded  = c.awardedCapacity;
  else 
    a.push({
      supplierName: c.supplierName,
      totalAwarded: c.awardedCapacity
    });
  
  return a;
}, []);

console.log(result);

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標籤：javascript 算法

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