這個問題在這里已經有了答案： 要求用戶輸入，直到他們給出有效回應 （21 個回答） 3 天前關閉。
我想問用戶他們是否想再次玩，如果他們想，代碼應該重復。我不確定如何。這是我的代碼：
import random
import time
seconds = input ("How many seconds?")
seconds = int(seconds)
a_list = input('What items do you want? haikyu/mha/demon slayer')
if a_list == 'haikyu':
items = ['hinata' 'kageyama', 'tsukishima', 'bokuto', 'kuroo', 'akaashi']
if a_list == 'mha':
items = ['denki', 'bakugo', 'kirishima', 'deku', 'todoroki', 'tsu']
if a_list == 'demon slayer':
items = ['tanjiro', 'nezuko', 'inosuke', 'zenitsu', 'tomioka']
random.shuffle(items)
for item in items:
print (item)
time.sleep(seconds)
random.shuffle(items)
removed_item = items.pop()
for item in items:
print(item)
guess = ''
while guess != removed_item:
guess = input('what is the missing item?')
uj5u.com熱心網友回復：
將所有這些放在一個函式中。然后，您的主要代碼只需執行以下操作：
while True:
game()
if input("Do you want to play again? (y/n): ") == "n":
break
uj5u.com熱心網友回復：
您的縮進似乎很差，要回答您的問題，您可以在最后一行中添加另一個條件：
while (guess != removed_item) and (retry != "No"):
retry = input("Would you like to try again? Y/N")
if retry == "Y":
guess = input('what is the missing item?')
else:
break
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