對python中的元組串列進行排序

我有這樣的元組

[('AVAX', '070122'), ('AVAX', '201221'), ('AVAX', '211221'), ('AVAX', '241221'), ('AVAX', '311221'), ('BNB', '070122'), ('BNB', '201221'), ('BNB', '211221'), ('BNB', '241221'), ('BNB', '280122'), ('BNB', '311221'), ('BTC', '070122'), ('BTC', '201221'), ('BTC', '211221'), ('BTC', '241221'), ('BTC', '250222'), ('BTC', '250322'), ('BTC', '280122'), ('BTC', '311221'), ('ETH', '070122'), ('ETH', '201221'), ('ETH', '211221'), ('ETH', '241221'), ('ETH', '250222'), ('ETH', '250322'), ('ETH', '280122'), ('ETH', '311221'), ('MATIC', '070122'), ('MATIC', '201221'), ('MATIC', '211221'), ('MATIC', '241221'), ('MATIC', '311221'), ('SOL', '070122'), ('SOL', '201221'), ('SOL', '211221'), ('SOL', '241221'), ('SOL', '280122'), ('SOL', '311221')]

這些是硬幣及其到期日。日期是字串格式，所以排列有誤。

所以我已經將格式更改為日期并嘗試安排。我試過下面的代碼。

filtered_final_product_list = [list(ele) for ele in filtered_final_product_list]
new_list=list()
for i in filtered_final_product_list:
    i[1]=datetime.strptime(i[1],'%d%m%y')
    new_list.append(i)
    
print(sorted(new_list))

結果和預期的一樣。

[['AVAX', datetime.datetime(2021, 12, 20, 0, 0)], ['AVAX', datetime.datetime(2021, 12, 21, 0, 0)], ['AVAX', datetime.datetime(2021, 12, 24, 0, 0)], ['AVAX', datetime.datetime(2021, 12, 31, 0, 0)], ['AVAX', datetime.datetime(2022, 1, 7, 0, 0)], ['BNB', datetime.datetime(2021, 12, 20, 0, 0)], ['BNB', datetime.datetime(2021, 12, 21, 0, 0)], ['BNB', datetime.datetime(2021, 12, 24, 0, 0)], ['BNB', datetime.datetime(2021, 12, 31, 0, 0)], ['BNB', datetime.datetime(2022, 1, 7, 0, 0)], ['BNB', datetime.datetime(2022, 1, 28, 0, 0)], ['BTC', datetime.datetime(2021, 12, 20, 0, 0)], ['BTC', datetime.datetime(2021, 12, 21, 0, 0)], ['BTC', datetime.datetime(2021, 12, 24, 0, 0)], ['BTC', datetime.datetime(2021, 12, 31, 0, 0)], ['BTC', datetime.datetime(2022, 1, 7, 0, 0)], ['BTC', datetime.datetime(2022, 1, 28, 0, 0)], ['BTC', datetime.datetime(2022, 2, 25, 0, 0)], ['BTC', datetime.datetime(2022, 3, 25, 0, 0)], ['ETH', datetime.datetime(2021, 12, 20, 0, 0)], ['ETH', datetime.datetime(2021, 12, 21, 0, 0)], ['ETH', datetime.datetime(2021, 12, 24, 0, 0)], ['ETH', datetime.datetime(2021, 12, 31, 0, 0)], ['ETH', datetime.datetime(2022, 1, 7, 0, 0)], ['ETH', datetime.datetime(2022, 1, 28, 0, 0)], ['ETH', datetime.datetime(2022, 2, 25, 0, 0)], ['ETH', datetime.datetime(2022, 3, 25, 0, 0)], ['MATIC', datetime.datetime(2021, 12, 20, 0, 0)], ['MATIC', datetime.datetime(2021, 12, 21, 0, 0)], ['MATIC', datetime.datetime(2021, 12, 24, 0, 0)], ['MATIC', datetime.datetime(2021, 12, 31, 0, 0)], ['MATIC', datetime.datetime(2022, 1, 7, 0, 0)], ['SOL', datetime.datetime(2021, 12, 20, 0, 0)], ['SOL', datetime.datetime(2021, 12, 21, 0, 0)], ['SOL', datetime.datetime(2021, 12, 24, 0, 0)], ['SOL', datetime.datetime(2021, 12, 31, 0, 0)], ['SOL', datetime.datetime(2022, 1, 7, 0, 0)], ['SOL', datetime.datetime(2022, 1, 28, 0, 0)]]

現在，當我想回到我在字串中提到的舊格式時，它的順序不同。它進入未排序的方式。最后需要幫助以字串格式排序。

uj5u.com熱心網友回復：

使用硬幣和日期排序datetime.datetime：

from datetime import datetime
sorted(lst, key=lambda x:(x[0], datetime.strptime(x[1], '%d%m%y')))

輸出：

[('AVAX', '201221'), ('AVAX', '211221'), ('AVAX', '241221'), 
 ('AVAX', '311221'), ('AVAX', '070122'), ('BNB', '201221'), 
 ('BNB', '211221'), ('BNB', '241221'), ('BNB', '311221'), 
 ('BNB', '070122'), ('BNB', '280122'), ('BTC', '201221'),
 ('BTC', '211221'), ('BTC', '241221'), ('BTC', '311221'), 
 ('BTC', '070122'), ('BTC', '280122'), ('BTC', '250222'), 
 ('BTC', '250322'), ('ETH', '201221'), ('ETH', '211221'), 
 ('ETH', '241221'), ('ETH', '311221'), ('ETH', '070122'), 
 ('ETH', '280122'), ('ETH', '250222'), ('ETH', '250322'), 
 ('MATIC', '201221'), ('MATIC', '211221'), ('MATIC', '241221'), 
 ('MATIC', '311221'), ('MATIC', '070122'), ('SOL', '201221'),
 ('SOL', '211221'), ('SOL', '241221'), ('SOL', '311221'), 
 ('SOL', '070122'), ('SOL', '280122')]

uj5u.com熱心網友回復：

這將按照您的要求執行，但正如我所說，您最好以正確的格式開始生成這些帶有日期的元組。

product_list = [('AVAX', '070122'), ('AVAX', '201221'), ('AVAX', '211221'), ('AVAX', '241221'), ('AVAX', '311221'), ('BNB', '070122'), ('BNB', '201221'), ('BNB', '211221'), ('BNB', '241221'), ('BNB', '280122'), ('BNB', '311221'), ('BTC', '070122'), ('BTC', '201221'), ('BTC', '211221'), ('BTC', '241221'), ('BTC', '250222'), ('BTC', '250322'), ('BTC', '280122'), ('BTC', '311221'), ('ETH', '070122'), ('ETH', '201221'), ('ETH', '211221'), ('ETH', '241221'), ('ETH', '250222'), ('ETH', '250322'), ('ETH', '280122'), ('ETH', '311221'), ('MATIC', '070122'), ('MATIC', '201221'), ('MATIC', '211221'), ('MATIC', '241221'), ('MATIC', '311221'), ('SOL', '070122'), ('SOL', '201221'), ('SOL', '211221'), ('SOL', '241221'), ('SOL', '280122'), ('SOL', '311221')]

product_list.sort( key=lambda k: (k[0],k[1][4:6] k[1][2:4] k[1][0:2]))
print(product_list)

uj5u.com熱心網友回復：

當您想要創建 new_list 并想要備份現有串列時

注意：sorted() :-> 創建一個新串列

借用@manlai A 的代碼：謝謝分享你的答案

   from datetime import datetime
    new_list = sorted(lst, key=lambda x:(x[0], datetime.strptime(x[1], '%d%m%y')))
    print(new_list)

當您想修改現有串列時

注意： given_list_obj.sort(key=function) :-> 對現有串列進行排序

new_list1 = lst.copy()
new_list1.sort(key=lambda x:(x[0], datetime.strptime(x[1], '%d%m%y')))
print(new_list)

輸出

    [('AVAX', '201221'), ('AVAX', '211221'), ('AVAX', '241221'), 
 ('AVAX', '311221'), ('AVAX', '070122'), ('BNB', '201221'), 
 ('BNB', '211221'), ('BNB', '241221'), ('BNB', '311221'), 
 ('BNB', '070122'), ('BNB', '280122'), ('BTC', '201221'),
 ('BTC', '211221'), ('BTC', '241221'), ('BTC', '311221'), 
 ('BTC', '070122'), ('BTC', '280122'), ('BTC', '250222'), 
 ('BTC', '250322'), ('ETH', '201221'), ('ETH', '211221'), 
 ('ETH', '241221'), ('ETH', '311221'), ('ETH', '070122'), 
 ('ETH', '280122'), ('ETH', '250222'), ('ETH', '250322'), 
 ('MATIC', '201221'), ('MATIC', '211221'), ('MATIC', '241221'), 
 ('MATIC', '311221'), ('MATIC', '070122'), ('SOL', '201221'),
 ('SOL', '211221'), ('SOL', '241221'), ('SOL', '311221'), 
 ('SOL', '070122'), ('SOL', '280122')]

標籤：Python 日期 约会时间 数据结构

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