我想制作一個應用程式，您必須在其中猜測兩個等于亂數的數字。但是我的應用程式在開始時崩潰了，因為 java.lang.NumberFormatException: For input string: ""
val intNumber1 = etNumber1.text.toString().toInt() 是導致崩潰的那一行。但我不知道該怎么辦。
這是我的主要活動：
//Buttons und Text initialisieren
private lateinit var btnCheck: Button
private lateinit var tvRndNumber: TextView
private lateinit var etNumber1: EditText
private lateinit var etNumber2: EditText
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
//Buttons und Text verknüpfen
btnCheck = findViewById(R.id.checkButton)
tvRndNumber = findViewById(R.id.randomNumber)
etNumber1 = findViewById(R.id.inputNumber1)
etNumber2 = findViewById(R.id.inputNumber2)
val intNumber1 = etNumber1.text.toString().toInt()
val intNumber2 = etNumber2.text.toString().toInt()
fun getRandomNumber(): Int {
return Random.nextInt(0,100)
}
var intRdnNumber = getRandomNumber()
tvRndNumber.text = intRdnNumber.toString()
fun checkNumbers(num1: Int, num2: Int){
if (num1 num2 == intRdnNumber) {
tvRndNumber.text = "Richtig"
}
else {
Toast.makeText(this,"Probier es nochmal", Toast.LENGTH_LONG).show()
}
}
btnCheck.setOnClickListener {
checkNumbers(intNumber1, intNumber2)
}
uj5u.com熱心網友回復：
嘗試如下
//....
val intNumber1 = etNumber1.text.toString()
val intNumber2 = etNumber2.text.toString()
//.....
btnCheck.setOnClickListener {
if(intNumber1.isNotEmpty && intNumber2.isNotEmpty{
checkNumbers(intNumber1.toInt(), intNumber2.toInt())
}else{
// input filed is empty
// show message or do nothing
}
}
uj5u.com熱心網友回復：
val intNumber1 = if(etNumber1.text.isNotEmpty()) {
etNumber1.text.toString().toInt()
} else {
0
}
val intNumber2 = if(etNumber2.text.isNotEmpty()) {
etNumber2.text.toString().toInt()
} else {
0
}
轉載請註明出處，本文鏈接：https://www.uj5u.com/net/396128.html
下一篇：未使用共享首選項保存資料