由此
import sympy as sp
x,y,z = sp.symbols("x y z")
sp.Ep(x,y/z)
對此
#varibles = array
#equation = ????
def solver(variables,equation):
#Looping through variables array and converting variables to sympy objects
for var in variables:
var = sp.symbols(var)
#Generate sympy Equation
equation = sp.Ep(equation)
variables = [x,y,z]
equation = x,y/z #invalid code
solver(variables,equation)
我正在創建一個函式，該函式能夠接收具有 x 個變數和 x-1 個值的方程，然后以符號方式求解缺失的變數，然后使用提供的值回傳數字答案。
我只包含了一小部分代碼，在這些代碼中我無法理解如何傳遞方程。任何解決方案或指標都會非常有用。謝謝。
uj5u.com熱心網友回復：
關于 Python 變數和用于變數的 SymPy 物件（符號），這里有幾層潛在的混淆。
這是你所說的一個例子：
# 3 variables
syms = x, y, z = var('x:z')
# 2 values
vals = {x:1, y:2}
# an equations
eq = Eq(x, y/z)
# solve for the missing value symbolically
missing = set(syms) - set(vals) # == {z}
solve(eq, missing)
[y/x]
# solve for the missing value after substituting in the known values
solve(eq.subs(vals))
[2]
您可以讓求解器接受一個方程，然后指定值并找出缺失的值并通過執行以下操作回傳該值：
>>> def solver(eq, **vals):
... from sympy.core.containers import Dict
... from sympy.solvers.solvers import solve
... free = eq.free_symbols
... vals = Dict(vals)
... x = free - set(vals)
... if len(x) != 1:
... raise ValueError('specify all but one of the values for %s' % free)
... x = x.pop()
... return solve(eq.subs(vals), x, dict=True)
...
>>> solver(eq, x=1, z=2)
[{y: 2}]
這是否給您一些關于如何繼續的想法？
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