我正在撰寫一個腳本，該腳本可以將 .json 格式轉換為 .idf 格式，以便在 EnergyPlus 中進行能量模擬。作為該腳本的一部分，我需要根據給定時間之前的多個時間點和值創建計劃。例如，這是我要轉換的 .json 元素之一：
"BOT": {"SpacesInModel": [
{"IndoorClimateZone": {
"Schedules": {
"PeopleSchedule": {"Timer": [
{ "$numberInt": "0" },
{ "$numberInt": "10" },
{ "$numberInt": "20" },
{ "$numberInt": "24" }
],
"Load": [{ "$numberDouble": "0.5" }, { "$numberInt": "1" }, { "$numberDouble": "0.5" }]
}
我目前創建了以下代碼，用于讀取和寫入 .idf 檔案所需的輸入，但我想將其作為 for 回圈而不是多個 if 陳述句來執行
### Define helper function determining the number format
def IntOrDouble(path_string):
try:
return_value = path_string["$numberInt"]
except Exception:
return_value = path_string["$numberDouble"]
return(return_value)
### Create .idf object and loop over .json format extracting schedule inputs
for item in data['BOT']['SpacesInModel']:
InputFile.newidfobject("Schedule:Day:Interval") #.idf object
DailySchedule = InputFile.idfobjects["Schedule:Day:Interval"][-1]
People_Time = item["IndoorClimateZone"]["Schedules"]["PeopleSchedule"]["Timer"]
People_Load = item["IndoorClimateZone"]["Schedules"]["PeopleSchedule"]["Load"]
if len(People_Time) >= 0 and len(People_Time) != 0:
DailySchedule.Time_2 = IntOrDouble(People_Time[0])
if len(People_Time) >= 1 and len(People_Time) != 1:
DailySchedule.Time_2 = IntOrDouble(People_Time[1])
DailySchedule.Value_Until_Time_2 = IntOrDouble(People_Load[0])
if len(People_Time) >= 2 and len(People_Time) != 2:
DailySchedule.Time_3 = IntOrDouble(People_Time[2])
DailySchedule.Value_Until_Time_3 = IntOrDouble(People_Load[1])
if len(People_Time) >= 3 and len(People_Time) != 3:
DailySchedule.Time_4 = IntOrDouble(People_Time[3])
DailySchedule.Value_Until_Time_4 = IntOrDouble(People_Load[2])
if len(People_Time) >= 4 and len(People_Time) != 4:
DailySchedule.Time_5 = IntOrDouble(People_Time[4])
DailySchedule.Value_Until_Time_4 = IntOrDouble(People_Load[3])
我的問題是我不知道如何將變數DailySchedule與可變物件名稱 /path （例如Time_1或Load_4. 的索引Time_i Load_i必須遵循 for 回圈的索引。到目前為止，這是我得到的最接近的（知道這不是一個真正的解決方案:-)）
for i in range(len(People_Time)):
DailySchedule."Time_{0}".format(i 1) = IntOrDouble(People_Time[i 1])
DailySchedule."Load_{0}".format(i 1) = IntOrDouble(People_Load[i])
uj5u.com熱心網友回復：
您可以使用pythons“ F-strings ”將變數添加到字串和方括號表示法以訪問字典中的專案。
for i in range(len(People_Time)):
DailySchedule[f"Time_{i 1}"] = IntOrDouble(People_Time[i 1])
DailySchedule[f"Time_{i}"] = IntOrDouble(People_Load[i])
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