我正在嘗試遍歷陣列內的物件內的陣列，并獲取所有科目匹配的教師。這是嵌套陣列 Teacher：
teachers: [
{name: "Dave", subjects: ["english", "math"]},
{name: "Jamal", subjects: ["history", "science"]},
{name: "Brian", subjects: ["science", "gym"]},
{name: "Sally", subjects: ["math", "history"]}
]
這是主題陣列：
subjects: ["english", "gym"]
我希望能夠讓所有有“英語”和“體操”科目的老師都能參加。所以基本上需要取回一個輸出：
teachers: [
{name: "Dave", subjects: ["english", "math"]},
{name: "Brian", subjects: ["science", "gym"]}
]
到目前為止，這是我想出的，但這只會渲染第一個包含“english”的物件，即 Dave。我意識到并回傳使它退出回圈，但我必須添加并回傳，否則它將是一個雙重渲染錯誤。答案很可能是一種完全不同的方式，因此任何方法都會受到贊賞！
subjects.each do |subject|
Teacher.all.each do |teach|
if (teach.subjects).include?(subject) then
render json: teach and return
end
end
end
teachers: [
{name: "Dave", subjects: ["english", "math"]}
]
我怎樣才能讓回圈也能找回布賴恩？
uj5u.com熱心網友回復：
聽起來您正在尋找任何教授主題陣列中任何科目的老師，所以：
teachers = [
{name: "Dave", subjects: ["english", "math"]},
{name: "Jamal", subjects: ["history", "science"]},
{name: "Brian", subjects: ["science", "gym"]},
{name: "Sally", subjects: ["math", "history"]}
]
subjects = ["english", "gym"]
teachers.select do |teacher|
(subjects & teacher[:subjects]).size > 0
end
ampersane 運算子是陣列元素之間的交集 - 換句話說，兩者中的值。
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