創建嵌套的subdictpython

我在串列中有一些不同型別的學生姓名和每種型別的分數。例如：

students_exam_names = [exam_name1, exam_name2, exam_name3]
students_exam_score = [exam_score1, exam_score2, exam_score3]
students_quiz_names = [quiz_name1, quiz_name2]
students_quiz_score = [quiz_score1, quiz_score2]
students_homework_names = [homework_name1, homework_name2, homework_name3, homework_name4]
students_homework_score = [homework_score1, homework_score2, homework_score3, homework_score4]

同樣適用于所有三個，如下所示。

我想以嵌套字典的形式獲得詳細資訊，如下所示：

details = {'students_exam':{
    'exam_name1':exam_score1,
    'exam_name2':exam_score2,
    'exam_name3':exam_score3
},
'students_quiz':{
    'quiz_name1': quiz_score1,
    'quiz_name2': quiz_score2
},
'students_homework':{
    'homework_name1': homework_score1,
    'homework_name2': homework_score2,
    'homework_name3': homework_score3,
    'homework_name4': homework_score4,
}

每個學生型別的長度是不同的。我試圖以如下字典串列的形式獲取它，但無法更進一步。

students_exam = {}

for i in range(len(students_exam_names)):
  students_exam[students_exam_names[i]] = students_exam_score[i]

uj5u.com熱心網友回復：

'在定義輸入時不要忘記使用：

students_exam_names = ['exam_name1', 'exam_name2', 'exam_name3']
students_exam_score = ['exam_score1', 'exam_score2', 'exam_score3']
students_quiz_names = ['quiz_name1', 'quiz_name2']
students_quiz_score = ['quiz_score1', 'quiz_score2']
students_homework_names = ['homework_name1', 'homework_name2', 'homework_name3', 'homework_name4']
students_homework_score = ['homework_score1', 'homework_score2', 'homework_score3', 'homework_score4']

然后，只需使用 zip 功能：

details = {'students_exam': dict(zip(students_exam_names, students_exam_score)),
           'students_quiz': dict(zip(students_quiz_names, students_quiz_score)),
           'students_homework': dict(zip(students_homework_names, students_homework_score))}

輸出是：

{'students_exam': {'exam_name1': 'exam_score1', 'exam_name2': 'exam_score2', 'exam_name3': 'exam_score3'}, 'students_quiz': {'quiz_name1': 'quiz_score1', 'quiz_name2': 'quiz_score2'}, 'students_homework': {'homework_name1': 'homework_score1', 'homework_name2': 'homework_score2', 'homework_name3': 'homework_score3', 'homework_name4': 'homework_score4'}}

uj5u.com熱心網友回復：

那么，如果我假設您的完整輸入集就像

students_exam_names = ['name1', 'name2', 'name3']
students_exam_score = ['score1', 'score2', 'score3']
students_quiz_names = ['name1', 'name2']
students_quiz_score = ['score1', 'score2']
students_homework_names = ['name1', 'name2', 'name3', 'name4']
students_homework_score = ['score1', 'score2', 'score3', 'score4'] 

如果是這樣，那么下面的代碼應該可以完成這項作業。

details={}
details['students_exam']={sexam: students_exam_score[students_exam_names.index(sexam)] for sexam in students_exam_names}
details['students_quiz']={squiz: students_quiz_score[students_quiz_names.index(squiz)] for squiz in students_quiz_names}
details['students_homework']={shome: students_homework_score[students_homework_names.index(shome)] for shome in students_homework_names}

uj5u.com熱心網友回復：

看起來您需要一些函式來執行這些更新：

def update_exam(details, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details['students_exam'] = results

def update_quiz(details, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details['students_quiz'] = results

def update_homework(details, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details['students_homework'] = results

details = {}
update_exam(details, students_exam_names, students_exam_score)
update_quiz(details, students_quiz_names, students_quiz_score)
update_homework(details, students_homework_names, students_homework_score)

但由于上述函式僅在鍵的文本名稱上有所不同，因此可以進一步折疊它們：

def update(details, key, names, scores):
    results = {}
    for name,score in zip(names,scores):
        results[name]=score
    details[key] = results

details = {}

update(details,'students_exam', students_exam_names, students_exam_score)
update(details,'students_quiz', students_quiz_names, students_quiz_score)
update(details,'students_homework', students_homework_names, students_homework_score)

然后回圈可以變成字典理解：

def update(details, key, names, scores):
    details[key] = {name:score for (name,score) in zip(names,scores)}

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