我有一個嵌套串列如下：
my_list = [['id_1', {'frame':[{'door': 'window', 'closet':'pinches'}], 'utterance':'sentence number 1', 'speaker':'silver'}],
['id_2',{'frame':[{'door': 'window', 'closet':'pinches'},{'door': 'new_door', 'closet':'hinges'}], 'utterance':'sentence number 2', 'speaker':'silver'}],
['id_3', {'frame':[{'door': 'window', 'closet':'pins'}], 'utterance':'sentence number 3', 'speaker':'gold'}]]
如果它包含值“gold”，我想從 my_list 中洗掉一個串列，所以我做了以下操作。
removed =[i for i in [item[1] for item in my_list] if not(i['speaker'] == 'gold')]
print(removed)
#output: [{'frame': [{'door': 'window', 'closet': 'pinches'}], 'utterance': 'sentence number 1', 'speaker': 'silver'}, {'frame': [{'door': 'window', 'closet': 'pinches'}, {'door': 'new_door', 'closet': 'hinges'}], 'utterance': 'sentence number 2', 'speaker': 'silver'}]
但我想保留'id_number'，所以我想要的輸出是：
my_new_list = [['id_1', {'frame':[{'door': 'window', 'closet':'pinches'}], 'utterance':'sentence number 1', 'speaker':'silver'}],
['id_2',{'frame':[{'door': 'window', 'closet':'pinches'},{'door': 'new_door', 'closet':'hinges'}], 'utterance':'sentence number 2', 'speaker':'silver'}]]
uj5u.com熱心網友回復：
我認為您只需要“切換” 2個行內回圈：
removed =[item for item in my_list if not(item[1]['speaker'] == 'gold')]
uj5u.com熱心網友回復：
嘗試這個：
my_list = [['id_1', {'frame':[{'door': 'window', 'closet':'pinches'}], 'utterance':'sentence number 1', 'speaker':'silver'}],
['id_2',{'frame':[{'door': 'window', 'closet':'pinches'},{'door': 'new_door', 'closet':'hinges'}], 'utterance':'sentence number 2', 'speaker':'silver'}],
['id_3', {'frame':[{'door': 'window', 'closet':'pins'}], 'utterance':'sentence number 3', 'speaker':'gold'}]]
new_list = []
new_list.extend([i for i in my_list if i[1]['speaker'] != "gold" ])
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