我有以下文字：
text_main = "The following leagues were identified: sport: basketball league: N.B.A. style: c.123>d sport: soccer league: E.P.L. sport: football league: N.F.L. style: c.124>d. The other leagues aren't that important."
我需要提取所有運動名稱（在 之后sport:）和風格（在之后style:）并創建新列作為sports和style。我正在嘗試使用以下代碼來提取主句（有時文本很大）：
m = re.split(r'(?<=\.)\s (?=[A-Z]\w )', text_main)
text = list(filter(lambda x: re.search(r'leagues were identified', x, flags=re.IGNORECASE), m))[0]
print(text)
The following leagues were identified: sport: basketball league: N.B.A. style: c.123>d sport: soccer league: E.P.L. sport: football league: N.F.L. style: c.124>d.
然后我提取運動和風格名稱并將它們放入資料框中：
if 'sport:' in text:
sport_list = re.findall(r'sport:\W*(\w )', text)
df = pd.DataFrame({'sports': sport_list})
print(df)
sports
0 basketball
1 soccer
2 football
但是，我在提取樣式時遇到了麻煩，因為所有樣式.在第一個字母 ( c) 之后都有句點，而很少有 sign >。此外，并非所有運動都有風格資訊。
期望的輸出：
sports style
0 basketball c.123>d
1 soccer NA
2 football c.124>d
最聰明的做法是什么？任何建議，將不勝感激。謝謝！
uj5u.com熱心網友回復：
您可以使用
\bsport:\s*(\w )(?:(?:(?!\bsport:).)*?\bstyle:\s*(\S ))?
請參閱正則運算式演示。詳情：
\b- 單詞邊界sport:- 固定字串\s*- 零個或多個空格(\w )- 第 1 組：一個或多個單詞字符(?:- 一個可選的非捕獲組的開始：(?:(?!\bsport:).)*?- 除換行符以外的任何字符，零次或多次出現但盡可能少，不會開始整個單詞sport:字符序列\bstyle:- 一個完整的詞style，然后:\s*- 零個或多個空格(\S )- 第 1 組：一個或多個非空白字符
)?- 可選非捕獲組的結束。
查看 Python 演示：
import pandas as pd
text_main = "The following leagues were identified: sport: basketball league: N.B.A. style: c.123>d sport: soccer league: E.P.L. sport: football league: N.F.L. style: c.124>d. The other leagues aren't that important."
matches = re.findall(r'\bsport:\s*(\w )(?:(?:(?!\bsport:).)*?\bstyle:\s*(\S ))?', text_main)
df = pd.DataFrame(matches, columns=['sports', 'style'])
輸出：
>>> df
sports style
0 basketball c.123>d
1 soccer
2 football c.124>d.
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